[Dot Product] Vector Proection

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SUMMARY

The discussion centers on the mathematical concept of vector projection and its relationship to the dot product. Participants clarify that to demonstrate two vectors are orthogonal, one must show that their dot product equals zero, specifically through the expression \(\vec a \cdot \vec w = 0\). The conversation emphasizes the importance of applying calculation rules for dot products, such as \(\vec a \cdot (\vec b+\vec c) = \vec a \cdot \vec b + \vec a \cdot \vec c\). Ultimately, the user successfully resolves their query regarding vector projection.

PREREQUISITES
  • Understanding of vector operations, specifically dot products
  • Familiarity with vector projection concepts
  • Knowledge of orthogonality in vector spaces
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of dot products in vector algebra
  • Learn about vector projection formulas and their applications
  • Explore orthogonality conditions in higher-dimensional spaces
  • Practice simplifying vector expressions using algebraic rules
USEFUL FOR

Students studying linear algebra, mathematicians, and anyone interested in understanding vector projections and their applications in various fields such as physics and engineering.

Highway
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[Dot Product] Vector Projection

Homework Statement



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Homework Equations



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The Attempt at a Solution



I am not sure what to do here -- I know that the projection of u onto a "dotted" with w = 0 by definition, but I don't know how to show this.

X0lLw.jpg


JldYG.jpg


added this second part after plugging in for the definition of the projection we derived in class, then simplified. . .
 
Last edited:
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anyone?
 
Hi Highway! :smile:

You have an expression for the projection.
Can you substitute that (and only that) in the formula you have for w?

To show that 2 vectors are orthogonal, you need to show that their dot product is zero. That is, that [itex]\vec a \cdot \vec w = 0[/itex].

What you need to know, is that there are calculation rules for dot products.
For instance [itex]\vec a \cdot (\vec b+\vec c) = \vec a \cdot \vec b + \vec a \cdot \vec c[/itex].

Can you simplify the expression for [itex]\vec a \cdot \vec w = 0[/itex]?
 
I like Serena said:
Hi Highway! :smile:

You have an expression for the projection.
Can you substitute that (and only that) in the formula you have for w?

To show that 2 vectors are orthogonal, you need to show that their dot product is zero. That is, that [itex]\vec a \cdot \vec w = 0[/itex].

What you need to know, is that there are calculation rules for dot products.
For instance [itex]\vec a \cdot (\vec b+\vec c) = \vec a \cdot \vec b + \vec a \cdot \vec c[/itex].

Can you simplify the expression for [itex]\vec a \cdot \vec w = 0[/itex]?

Thanks! I got it figured out :P

M0r1c.jpg
 
Congrats! :wink:
 

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