Lead (II) nitrate + manganese (IV) iodide -> _______
2. The attempt at a solution
So I think I know how to do this
2 Pb(NO3)2 + MnI4 -> 2 PbI2 + Mn(NO3)4
I'm just a bit confused because with single displacement you have to check the activity series? And so I'm not sure if I need to use the activity series for double displacement too? If not, how does I check to see if it will take place?