- #1
Hatmpatn
- 6
- 0
Hi! I'm stuck with the following problem:
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Calculate
∫∫ (x-y)*|ln(x+2y)| dxdy
where D is the triangle with corners in the coordinates (0,0), (1,1) and (-3,3)
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I get the following lines that forms the triangle: y=-x, y=x and y=-1/2*x+3/2
Im thinking that I start with substitution: (x-y)=u and x+2y=v
Which gives me ∫∫ u*|ln(v)| dudv
After that I don't know how to continue. I would like to know which new "intervals" I should do the integral between when I am in my new u- and v-domain?
-----------------------------------
Calculate
∫∫ (x-y)*|ln(x+2y)| dxdy
where D is the triangle with corners in the coordinates (0,0), (1,1) and (-3,3)
-----------------------------------
I get the following lines that forms the triangle: y=-x, y=x and y=-1/2*x+3/2
Im thinking that I start with substitution: (x-y)=u and x+2y=v
Which gives me ∫∫ u*|ln(v)| dudv
After that I don't know how to continue. I would like to know which new "intervals" I should do the integral between when I am in my new u- and v-domain?