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**Calculate**

∫∫

**(x-y)*|ln(x+2y)| dxdy**

**where D is the triangle with corners in the coordinates (0,0), (1,1) and (-3,3)**

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I get the following lines that forms the triangle:

**y=-x, y=x**and

**y=-1/2*x+3/2**

Im thinking that I start with substitution:

**(x-y)=u**and

**x+2y=v**

Which gives me

**∫∫ u*|ln(v)| dudv**

After that I don't know how to continue. I would like to know which new "intervals" I should do the integral between when I am in my new u- and v-domain?