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How would you find the volume in the first octant of the solid bounded by the cylinder y2+z2=9 and x=6?
I tried doing a double integral, both from 0 to 3 of (y2+z2)dydz then multiply by 6, but I keep getting 0.
I tried doing a double integral, both from 0 to 3 of (y2+z2)dydz then multiply by 6, but I keep getting 0.