Double Slit Diffraction Problem

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 2K views
spitonem
Messages
4
Reaction score
0
I had this problem on my exam and I was pretty sure i knew what to do but it couldn't come up with the right answers.
I diagrammed the problem and showed the way i tried to solve it in blue. Can someone tell me where i went wrong?
W6xA170.png


Basically i found the length the of the first maximum off the center. i used Pythagorean's theorem to find D2. Then subtracted the two distances to find the difference. I then took the arctan of that distance divided by D1.
 
Physics news on Phys.org
You way over-thought the problem.
Start from the physics: what is the condition that makes a maximum?
 
the center of a maximum is complete constructive interference from two rays of light?
 
the center of a maximum is complete constructive interference from two rays of light?
... good - so what is the condition for constructive interference in terms of the path lengths?
 
wouldn't it be the wavelength plus by any integer being multiplied by the wavelength?
 
wouldn't it be the wavelength plus by any integer being multiplied by the wavelength?
Almost: the path difference has to be a whole number of wavelengths for constructive interference.
This makes the central maximum the zeroth maximum ... with the 1st and second etc on either side of it.

Lets say D is the perpendicular distance from the slits to the screen - as it is in your diagram.
If D>>d, the path difference between the zeroth maximum and the nth maximum is ##D_n-D=d\sin\theta_n##
You've seen a formula like that before.