Double-Slit Experiment problem?

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In the double-slit experiment, the problem involves finding the distance of the first dark fringe from the central maximum, given that the third order bright fringe is 15 mm away. The relevant equations for dark and bright fringes are provided, but the lack of angle and wavelength information complicates the solution. A participant suggests using the approximation sin(theta) = theta = x/D, where x is the fringe displacement and D is the distance to the screen. The initial attempt to find the dark fringe distance by dividing the bright fringe distance by three is noted but deemed insufficient. The discussion emphasizes the need for additional parameters to solve the problem accurately.
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Homework Statement


In a double-slit experiment, the third order bright fringe is 15 mm from the central fringe. What is the distance of the first (zero-th order) dark fringe from the central maximum?

Homework Equations


(m+.5)(lambda) = dsin(theta) => dark fringe
m(lambda) = dsin(theta) => bright fringe

The Attempt at a Solution


I honestly don't know. Like, there's no angle or wavelength. The most I've come up with is 15 mm divided by 3 (because it's the third) and getting 5 mm. I seriously don't know.
 
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the equation you need is
dsinθ = nλ for maxima...you have this in your post
 
lychette said:
the equation you need is
dsinθ = nλ for maxima...you have this in your post

But where do I get the angle and wavelength from?
 
For angles this small you can use the approximation: sin theta = theta = x / D where x
is the fringe displacement from the central maximum and D is the distance to the screen.
 
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