Doubt about Electric Field calculations

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SUMMARY

The discussion centers on calculating the electric field intensity at a distance of 12.9 cm from the axis of a long, straight conductor with a charge density of 1.61 C/m. The relevant equation used is E = λ / (2πrε0), where λ represents the charge density, r is the distance from the axis, and ε0 is the permittivity of free space. It is established that the radius of the conductor (3.82 cm) is not necessary for the calculation, as the distance provided (12.9 cm) is sufficient for determining the electric field intensity.

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Homework Statement


Find the magnitude of an electric field intensity at a distance 12.9 cm, from the axis of a long, straight conductor, which has a radius 3.82 cm, and a charge density of 1.61 C/m.

Homework Equations


Gauss's law

The Attempt at a Solution


E= λ/2πrε0

Hello, I'm having some troubles understanding this question. To find E i would simply use the 12.9 cm radius, convert it into meters and use the above equation but if I do so I won't need the other information given of the radius of the conductor.
Do you agree with me? or should I add the 12.9 + the 3.82 radius and put that value into the equation?
thanks
 
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The problem clearly states that the 12.9 cm distance is the distance from the axis. The 3.82 cm information is a red herring.
 
thank you!
 

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