Doubts in special theory of relativity

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The discussion centers on the implications of Einstein's special theory of relativity regarding simultaneity in different reference frames. It is established that events simultaneous in one frame may not be simultaneous in another, particularly when considering motion along the x-axis. The participants explore the nuances of how observers perceive events based on their relative motion, emphasizing that time dilation affects moving observers differently than stationary ones. The conversation also highlights the importance of understanding the relativity of motion and the need to reframe intuitive concepts from classical physics. Ultimately, the conclusion drawn is that simultaneity is relative and dependent on the observer's frame of reference.
  • #91
One needs 4-d coordinate system with Lorentz metric. May be you think it was existed before SR?

And what is in SR that above the 4-d coordinate system with Lorentz metrics? May be Lorentz metrics itself?
 
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  • #92
altsci2 said:
One needs 4-d coordinate system with Lorentz metric. May be you think it was existed before SR?
And what is in SR that above the 4-d coordinate system with Lorentz metrics? May be Lorentz metrics itself?
Keep calm, I'm objecting to the terminology. I don't see the Minkowski metric as 'absolute space-time'.
 
  • #93
I agree with the objection. There is no reason to label Minkowski's spacetime "absolute".
 
  • #94
Both Mentz and Dale objections against the term "absolute". Also they rather use the term "Minkowski space" and "Minkowski metric".
Minkowski used imaginary time and Euclidean metric. Also he did not consider arbitrary transformations of coordinates. As far as we concerned with 4-d geometry I would better refer to Riemann approach with real axes and arbitrary transformations of coordinates. We always need to start with the coordinate system with rectilinear axes and prescribed metrics (the Lorentz Metrics). This coordinate system and this metrics describe the "Space of SR". We can call it "Minkowski Space" just to honor Minkowski. If you mean that - it is ok.
About "absolute". Having Minkowski coordinate system and given a trajectory of a point particle in it (numerical description) is enough to calculate acceleration in any point that will be the same in any other coordinate system (scalar) in the same point (points survive arbitrary transformation). The acceleration will be not relative, it will be "absolute" (no other reference is necessary except Minkovski space itself).
 
  • #95
altsci2 said:
Both Mentz and Dale objections against the term "absolute". Also they rather use the term "Minkowski space" and "Minkowski metric".
Minkowski used imaginary time and Euclidean metric. Also he did not consider arbitrary transformations of coordinates. As far as we concerned with 4-d geometry I would better refer to Riemann approach with real axes and arbitrary transformations of coordinates. We always need to start with the coordinate system with rectilinear axes and prescribed metrics (the Lorentz Metrics). This coordinate system and this metrics describe the "Space of SR". We can call it "Minkowski Space" just to honor Minkowski. If you mean that - it is ok.
It is standard terminology.
http://en.wikipedia.org/wiki/Minkowski_space
http://en.wikipedia.org/wiki/Pseudo-Riemannian_manifold#Lorentzian_manifold

altsci2 said:
About "absolute". Having Minkowski coordinate system and given a trajectory of a point particle in it (numerical description) is enough to calculate acceleration in any point that will be the same in any other coordinate system (scalar) in the same point (points survive arbitrary transformation). The acceleration will be not relative, it will be "absolute" (no other reference is necessary except Minkovski space itself).
I think the word you are looking for is "invariant". Here is a recent discussion on the topic.
https://www.physicsforums.com/showthread.php?t=600195
 
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  • #96
Some basic doubts I have are:
1) When doing thought experiment for Inertial frame moving with constant velocity and enclosed in box, when a ray of light starts, does it get detached from the box? If yes, we can detect the motion, correct?

2) When ray of light emits say from star, (and say they emit photons), the beam would diverge outwards. what happens to space between the two rays say trillion miles away from star? If there are no photons here, I should not see the star, correct?

Sorry for silly Q but it has been bothering me...
 
  • #97
Gadhav said:
Some basic doubts I have are:
1) When doing thought experiment for Inertial frame moving with constant velocity and enclosed in box, when a ray of light starts, does it get detached from the box? If yes, we can detect the motion, correct?
You can't use light to detect inertial motion because it will always travel at c.

2) When ray of light emits say from star, (and say they emit photons), the beam would diverge outwards. what happens to space between the two rays say trillion miles away from star? If there are no photons here, I should not see the star, correct?
In this situation it is better think of light as EM waves.
 
  • #98
Gadhav said:
Some basic doubts I have are:
1) When doing thought experiment for Inertial frame moving with constant velocity and enclosed in box, when a ray of light starts, does it get detached from the box? If yes, we can detect the motion, correct?

If you had a ball, it would not "detach from the box" and would appear at rest to you. Light, as you say, unlike the ball would be seen to be in motion. But of course it's always seen in motion, you can't slow it down, and so again you would not have an experience any different from what you expect at rest.

Gadhav said:
2) When ray of light emits say from star, (and say they emit photons), the beam would diverge outwards. what happens to space between the two rays say trillion miles away from star? If there are no photons here, I should not see the star, correct?

Even if you see it as particles and not EM waves, there's going to be countless photos generated and sent out into space every second. If the star only sent out a single wave/particle of light here and there, you might indeed fail to detect it from a specific location.
 
  • #99
That post says "Here is a transform which has the relativity of simultaneity, but not length contraction or time dilation: t′=t−vx, x′=x−vt. " Actually I think that transformation does entail some time dilation, although not reciprocal. A clock at rest in the primed coordinates would run slow by a factor of 1-v^2 relative to the unprimed coordinates. On the other hand, a clock at rest in the (unique) unprimed coordinates has no dilation relative to the primed coordinates.

To use any transformation other than Lorentz one has to know how to do it. It is much more complicated. SR build up upon LT and incorporated all the simplifications that LT provides. Now we stuck on LT. In Riemann Geometry the transformation is arbitrary but one has to know Riemann Geometry. The Lorentz Metrics invariant only with respect LT! certainly it will be not invariant with respect t'=t-vx, x'=x-vt
 
  • #100
Mentz114 said:
You can't use light to detect inertial motion because it will always travel at c.


In this situation it is better think of light as EM waves.

I think my point is that if light detached from the box and box moving, it will take more time for it to travel to end and less time when coming back. Speed at which it does should not matter.

Also Whether it is photon or EM wave, they all travel in st lines and diverge so in theory there can be areas where EMwave or photon will not reach, far away from star.

Sorry but I don't think I am convinced yet why it happens.
 
  • #101
What does this idea of "light detached from the box" even mean? I have never heard such a phrase and I have no idea how to interpret it.

It would help if you could use standard terminology as much as possible.

As far as you comment about straight lines goes, assuming that there is nothing absorbing the light and assuming that the star is spherically symmetric, then there is an equal probability of detecting a photon from a star in any direction due to symmetry. You can be so far away that the probability is extremely small, but it is always non-zero.
 
  • #102
Gadhav said:
I think my point is that if light detached from the box and box moving, it will take more time for it to travel to end and less time when coming back. Speed at which it does should not matter.

inside the box, light is measured to travel from one end of the box to the other and back, taking the same time each direction. It is measured moving each way at c.

Also Whether it is photon or EM wave, they all travel in st lines and diverge so in theory there can be areas where EMwave or photon will not reach, far away from star.
Sorry but I don't think I am convinced yet why it happens.

For any given photon, the further the EM wave gets from the source, the lower likelihood it will be absorbed / experienced at a particular location. In real life, there are high # of photons all coming together, and so the luminosity of photons absorbed/experienced per unit time will decrease for observers farther away.
 
  • #103
Gadhav said:
I think my point is that if light detached from the box and box moving, it will take more time for it to travel to end and less time when coming back. Speed at which it does should not matter.
Can you describe exactly the apparatus to detect this ?

Also Whether it is photon or EM wave, they all travel in st lines and diverge so in theory there can be areas where EMwave or photon will not reach, far away from star.
True, when the intensity of the light falls below the limit of detection then nothing will be seen. So what ?

These points are made in the other replies also.
 
  • #104
Mentz114 said:
Can you describe exactly the apparatus to detect this ?

Let us assume that a photon leaves one end of room. Room is moving right at "v" since photon is not acquiring room's velocity, it travels L+vt in forward direction and L-vt in reverse. Since the time is different, it can be detected.
This is same as MM Experiment. I understand that this logic works for point of view of observer outside. My Q is: why cannot person inside the box detect the same. Note that if particle acquired box's speed, it would be impossible to detect it (Ex: person in car) but photon does not and that is important.

The exact concept is not going in my head.
 
  • #105
Gadhav said:
Let us assume that a photon leaves one end of room. Room is moving right at "v" since photon is not acquiring room's velocity, it travels L+vt in forward direction and L-vt in reverse. Since the time is different, it can be detected.
This is same as MM Experiment. I understand that this logic works for point of view of observer outside. My Q is: why cannot person inside the box detect the same. Note that if particle acquired box's speed, it would be impossible to detect it (Ex: person in car) but photon does not and that is important.

The exact concept is not going in my head.
In the section I've highlighted, what is 'v' in 'L+vt' ?
 
  • #106
Gadhav said:
Let us assume that a photon leaves one end of room. Room is moving right at "v" since photon is not acquiring room's velocity, it travels L+vt in forward direction and L-vt in reverse. Since the time is different, it can be detected.
This is same as MM Experiment. I understand that this logic works for point of view of observer outside. My Q is: why cannot person inside the box detect the same. Note that if particle acquired box's speed, it would be impossible to detect it (Ex: person in car) but photon does not and that is important.

The exact concept is not going in my head.
The exact concept is what Einstein discussed in section 1 of his 1905 paper introducing SR. Please read and study that section and either tell us that the exact concept is now going in your head or tell us why you think that Einstein was wrong.
 
  • #107
Gadhav said:
Let us assume that a photon leaves one end of room. Room is moving right at "v" since photon is not acquiring room's velocity, it travels L+vt in forward direction and L-vt in reverse. Since the time is different, it can be detected.
This is same as MM Experiment. I understand that this logic works for point of view of observer outside. My Q is: why cannot person inside the box detect the same. Note that if particle acquired box's speed, it would be impossible to detect it (Ex: person in car) but photon does not and that is important.

The exact concept is not going in my head.

In the rooms frame of reference it's v = 0, so the photon moves 2L.
 
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  • #108
Gadhav said:
Let us assume that a photon leaves one end of room. Room is moving right at "v" since photon is not acquiring room's velocity, it travels L+vt in forward direction and L-vt in reverse. Since the time is different, it can be detected.
This is same as MM Experiment. I understand that this logic works for point of view of observer outside. My Q is: why cannot person inside the box detect the same. Note that if particle acquired box's speed, it would be impossible to detect it (Ex: person in car) but photon does not and that is important.

The exact concept is not going in my head.

Here is the deal.

For whatever reason, there have been many experiments that have proven no matter what you think the room is doing, the room measures c except for the Earth's rotational sagnac effect.

For example, the "room" "earth" rotates. travels around the sun, moves with the milky way and whatever else, but light still measures c in all directions as verified by GPS with the exception of the rotational sagnac effect.

These are the facts.

+
 
  • #109
JohnWisp said:
Here is the deal.

For whatever reason, there have been many experiments that have proven no matter what you think the room is doing, the room measures c except for the Earth's rotational sagnac effect.

For example, the "room" "earth" rotates. travels around the sun, moves with the milky way and whatever else, but light still measures c in all directions as verified by GPS with the exception of the rotational sagnac effect.

These are the facts.

+
You cannot measure the speed of light to be c in all directions. Instead, Einstein defines the speed of light to be c in all directions and then uses that to define an inertial reference frame. The sagnac effect does not apply as it is not inertial.
 
  • #110
ghwellsjr said:
You cannot measure the speed of light to be c in all directions. Instead, Einstein defines the speed of light to be c in all directions and then uses that to define an inertial reference frame. The sagnac effect does not apply as it is not inertial.

GPS proves the speed of light is measured c in all directions except for sagnac.

That is what I said.

Are you claiming this is false? See Neil Ashby.

http://relativity.livingreviews.org/Articles/lrr-2003-1/
 
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  • #111
JohnWisp said:
GPS proves the speed of light is measured c in all directions except for sagnac.

That is what I said.

Are you claiming this is false? See Neil Ashby.

http://relativity.livingreviews.org/Articles/lrr-2003-1/
I'm not disagreeing with the article. We cannot use just Special Relativity to design GPS because it operates under the influence of gravity. The fact that GPS works proves that the designers made a good choice when they used both Special Relativity and General Relativity to design it. But that does not change the fact that Special Relativity defines the speed of light to be c in all directions as opposed to measuring it independent of any theory.
 
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  • #112
JohnWisp said:
GPS proves the speed of light is measured c in all directions except for sagnac.

That is what I said.

Are you claiming this is false? See Neil Ashby.

http://relativity.livingreviews.org/Articles/lrr-2003-1/

Where does he say this? I see him state that it is defined to be c in all directions, not measured.
 
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  • #113
Vanadium 50 said:
Where does he say this? I see him state that it is defined to be c in all directions, not measured.

He responded to me and said not measured c in all directions but defined as c.

My post said light is measured c in all directions except for sagnac according to GPS.

Are you claiming this is false?
 
  • #114
ghwellsjr said:
I'm not disagreeing with the article. We cannot use just Special Relativity to design GPS because it operates under the influence of gravity. The fact that GPS works proves that the designers made a good choice when they used both Special Relativity and General Relativity to design it. But that does not change the fact that Special Relativity defines the speed of light to be c in all directions as opposed to measuring it independent of any theory.

Yes, I realize that.

But the Op is trying to understand how light is not measured c when it is in fact measured c.

The OP thinks it should be c+v and c-v.

GPS refutes this and that is what I was posting.
 
  • #115
The whole thread is tl;dr. But to the OP - any two events that are separated far enough from each other to require a faster than light speed to connect, are simultaneous in some reference frame. Such events are called space-like separated events. It is accepted than no causal relation between such events can exist.

On the other hand, any two events that are close enough to connect with slower-than-light speed in one reference frame are also separated similarly in all other reference frames. They are not simultaneous, nor in a reversed order in any other reference frame. Such events are called time-like separated events.
 
  • #116
georgir said:
The whole thread is tl;dr. But to the OP - any two events that are separated far enough from each other to require a faster than light speed to connect, are simultaneous in some reference frame. Such events are called space-like separated events. It is accepted than no causal relation between such events can exist.

On the other hand, any two events that are close enough to connect with slower-than-light speed in one reference frame are also separated similarly in all other reference frames. They are not simultaneous, nor in a reversed order in any other reference frame. Such events are called time-like separated events.
What does tl;dr mean?
 
  • #118
JohnWisp said:
ghwellsjr said:
I'm not disagreeing with the article. We cannot use just Special Relativity to design GPS because it operates under the influence of gravity. The fact that GPS works proves that the designers made a good choice when they used both Special Relativity and General Relativity to design it. But that does not change the fact that Special Relativity defines the speed of light to be c in all directions as opposed to measuring it independent of any theory.
Yes, I realize that.

But the Op is trying to understand how light is not measured c when it is in fact measured c.

The OP thinks it should be c+v and c-v.

GPS refutes this and that is what I was posting.
Again, we cannot measure the speed of light in any direction. We assign the speed of light to be c in all directions in any Inertial Reference Frame (IRF). Therefore, the time it takes for light to propagate from one spatial point to a second spatial point is only the same as it takes for the reflection to propagate back to the first point in an IRF in which the first spatial point is at rest because our definition of an IRF makes it so. In other IRFs moving along the direction between those two spatial points, the time it takes for the light to propagate along the same two paths in opposite directions are not equal.

There is no measurement, independent of previously assigning or assuming the two propagation paths to yield the same time, that will determine that they take the same time.

I don't know why this is so hard for you to accept. If you just think about Relativity of Simultaneity, you can easily see that the time it takes for light to go in two directions between two spatially separated points takes different times in different frames. Look at this post I just made for you in another thread:

https://www.physicsforums.com/showpost.php?p=4341630&postcount=30

In the first IRF diagram where the blue twin is not at rest, the time it takes for his signal to propagate to the red twin is not the same as the time it takes for the light to reflect back but in the second IRF diagram where the blue twin is at rest, the two times are equal.
 
  • #119
georgir said:
ghwellsjr said:
What does tl;dr mean?
http://lmgtfy.com/?q=tl;dr
One of the rules on this forum is:
All posts must be in English. Posts in other languages will be deleted. Pay reasonable attention to written English communication standards. This includes the use of proper grammatical structure, punctuation, capitalization, and spelling. SMS messaging shorthand ("text-message-speak"), such as using "u" for "you", and "please" for "please", is not acceptable.

Please follow the rules.
 
  • #120
ghwellsjr said:
Please follow the rules.
There is also a rule about off-topic discussions such as the one both of us are currently having. If you want, use the 'report' button on my post instead.
 

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