Draw a Circuit based on the info and find the voltage values

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SUMMARY

The discussion focuses on solving a circuit problem involving four nodes labeled a, b, c, and d, with known voltage values: vab = 12V, vcb = -4V, and vda = 8V. The goal is to determine the unknown voltages vac and vcd using Kirchhoff's voltage law, which states that the sum of voltages in a closed loop equals zero. Participants emphasize the importance of indicating polarity in voltage symbols and suggest simplifying the circuit diagram for clarity. The recommended approach includes labeling node potentials and calculating the required voltage differences based on established relationships.

PREREQUISITES
  • Understanding of Kirchhoff's voltage law
  • Ability to interpret circuit diagrams
  • Familiarity with voltage polarity and symbols
  • Basic knowledge of electrical potential differences
NEXT STEPS
  • Learn how to apply Kirchhoff's voltage law in complex circuits
  • Study the principles of voltage polarity and its representation in circuit diagrams
  • Explore methods for simplifying circuit diagrams for easier analysis
  • Practice calculating voltage differences in multi-node circuits
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Electrical engineering students, circuit designers, and anyone involved in analyzing or solving circuit problems will benefit from this discussion.

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Homework Statement


Consider a circuit containing four nodes
labeled a, b, c, and d. Also, we know that
vab= 12V,vcb=−4V,and vda= 8V. Deter-
mine the values of vac and vcd. (Hint: Draw
a picture showing the nodes and the known
voltages.)


Homework Equations


∑ voltages in a loop = 0


The Attempt at a Solution



I had no idea how to approach the problem, just a couple ideas. I tried sketching this out:

HczRsAL.png


This one didn't make much sense to me since applying the loop rule, I get differing answers for ##v_{ac}##

So I tried a few other ways to draw it and this was the closest I could get:

VsvrzhN.png


This seems like it makes more sense, but I'm not entirely sure. Am I on the right track?
 
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I recommend the first thing to change is you need to change your voltage symbol to indicate some sort of polarity. They blue squares alone are not sufficient. Either use a symbol with obvious polarity such as a battery symbol, or (and this is just as good too) label the '+' and '-' signs.

What I mean by that is if you look at the 8 V element in the upper left. Imagine, hypothetically, flipping the polarity of that element, making it VAD = 8 V. If you did so, it wouldn't look any different than the way it is now with VDA = 8 V. You need some way of indicating the polarity. You need to know by looking at your picture that if VDA = 8 V, then VAD = -8 V

Secondly, don't draw that stuff in the middle. It's not necessary. Just keep it as a square if you wish (or even three sides of a square), with nothing in the center. Note that VAC = VAB + VBC
 
It is easier to work with potentials. If Vab means the potential of b with respect to a : Vab=Vb-Va=12 V. Write 0 at point a and 12 V at point b. Draw a battery between the nodes to ensure the given potential difference.
Draw the batteries and determine the potential of each node. Calculate the potential differences Vac=Vc-Va and Vcd=Vd-Vc.

You can connect a resistor between two nodes and an other one between the other two nodes, the potential differences would not change.

ehild
 

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