Drawing a KMap for f(A,B,C): Step-by-Step Guide

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Discussion Overview

The discussion focuses on drawing a Karnaugh map (K-map) for the function f(A,B,C) = E m(0,1,3,6,7) and the subsequent simplification of the resulting expression. Participants explore the correct representation of the K-map and the implications of different simplified forms, including considerations of static hazards.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents a K-map layout and questions its correctness.
  • Another participant confirms the layout looks correct but suggests using code formatting for better spacing.
  • A simplified expression (AB + A'B' + A'C) is proposed by one participant, who notes that a simplification program also suggests an alternative (AB + A'B' + BC).
  • There is uncertainty expressed regarding the presence of static hazards in the simplified expressions, with one participant questioning if both answers are valid for the K-map.

Areas of Agreement / Disagreement

Participants generally agree on the correctness of the K-map layout, but there is disagreement regarding the implications of the different simplified expressions and the identification of static hazards.

Contextual Notes

There are unresolved questions about the conditions under which the different simplified expressions are valid and the criteria for identifying static hazards in the context of the K-map.

ckaiser813
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Draw a Kmap for

f(A,B,C) = E m(0,1,3,6,7)

I've had enough expirence with kmap through my digital courses to understand them, but I've never seen them described this way,

AB
00 01 11 10
C 0 1 0 1 0
C 1 1 1 1 0

Is this correct way of drawing it?
 
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ckaiser813 said:
Draw a Kmap for

f(A,B,C) = E m(0,1,3,6,7)

I've had enough expirence with kmap through my digital courses to understand them, but I've never seen them described this way,

AB
00 01 11 10
C 0 1 0 1 0
C 1 1 1 1 0

Is this correct way of drawing it?

Looks correct, but if you use the [ code ] [ / code ] tags (without spaces) around the table, it will preserve the spacings.

I haven't seen that notation before either...
 
Code:
     ab
     00 01 11 10
c 0  1  0   1  0
c 1  1  1   1  0
 
thanks for the help I than simplified it to (AB + A'B' + A'C), but when I use a simplifing program it says that I'm correct or it could also be (AB + A'B' + BC). I'm little confused with this one. My professor said once we simplified it we were suppose to find the Static 1 Hazard with this function, do you think the two different answers is what I'm looking for?
 
ckaiser813 said:
thanks for the help I than simplified it to (AB + A'B' + A'C), but when I use a simplifing program it says that I'm correct or it could also be (AB + A'B' + BC). I'm little confused with this one. My professor said once we simplified it we were suppose to find the Static 1 Hazard with this function, do you think the two different answers is what I'm looking for?

Both answer work for that K-map, and I think usually you would pick one based on other considerations (like availability of inverted signals, etc. I'm not seeing the hazard -- am I missing one?

http://en.wikipedia.org/wiki/Hazard_(logic )

.
 
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