Drawing a simple vector field issue

  • Thread starter mr_coffee
  • Start date
  • #1
1,629
1
Hello everyone i'm not sure if this is right or not...

If i have

F(x,y,z) = zj; where j is the vector, j hat.

Would that be all vectors are going to be pointing up if you assume z is up, and are in the y plane?


If the coordinate sytem is, z is up, y is to the right, and x is pointing at you.

If i had F(x,y,z) = yj; the answer is, No vectors emanate from the xz plane since y = 0 there. In each plane y = b, all the vectors are identical.
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,260
619
No. j is a unit vector pointing in the same direction as the +y axis. Which you seem to want to call 'right'. The length of the vectors is proportional to their z coordinate. What is the 'y plane'? What does 'in' a plane mean? Parallel to?
 
  • #3
1,629
1
I worked it out and it seems the vectors are pointing parrallel to the +y axis which is pointing right, for values > 0, and for values < 0 its pointing to the left or in the -y direction.
 
  • #4
Dick
Science Advisor
Homework Helper
26,260
619
I worked it out and it seems the vectors are pointing parrallel to the +y axis which is pointing right, for values > 0, and for values < 0 its pointing to the left or in the -y direction.
That's the right picture (where 'values' means z, right).
 
  • #5
HallsofIvy
Science Advisor
Homework Helper
41,833
961
z is a number, j is a vector pointing in the positive y direction. Your vector field consists of vector pointing in the positive y direction, longer as z increases. (And pointing in the negative y direction for z negative.)
 

Related Threads on Drawing a simple vector field issue

  • Last Post
Replies
1
Views
819
  • Last Post
Replies
4
Views
9K
Replies
5
Views
1K
Replies
4
Views
717
Replies
2
Views
7K
Replies
4
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
6
Views
2K
  • Last Post
Replies
4
Views
949
  • Last Post
Replies
9
Views
2K
Top