Drawing lemonade of density 1000 kg/m3 up a straw to a maximum height

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Homework Help Overview

The discussion revolves around calculating the minimum gauge pressure required to draw lemonade of a specific density up a straw to a certain height. The subject area includes fluid mechanics and pressure concepts.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the pressure formula P=pgh and question the conversion from mks units to atmospheres. There is also a focus on the implications of negative pressure in this context.

Discussion Status

The discussion is ongoing, with participants exploring the reasoning behind the negative pressure result and questioning the assumptions made in the calculations. Some guidance has been provided regarding unit conversion.

Contextual Notes

There is mention of the specific density of the lemonade and the maximum height involved in the problem. Participants are also considering the implications of gauge pressure and its potential to be negative.

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To suck lemonade of density 1000 kg/m3 up a straw to a maximum height of 3.3 cm, what minimum gauge pressure (in atmospheres) must you produce in your lungs?

I know i need to use P=pgh which equals 1000(9.81)(.033)
which equals 323.73
-Then i divide, so, 323.73/1.0125e5
that equals 3.197e-3

It said that my answer was wrong. It looks good to me. Thanks for the help.
 
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What's the conversion you are using from mks units to atmospheres?
 
You're answer better be negative.
 
thanks man, it was negative.
 


I just did this problem and was wondering why the answer was negative? How often can pressure be considered negative?

Thanks for the help!

~Phoenix
 

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