MHB Drawing the Venn Diagram for A ∩ Bc

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The discussion focuses on drawing the Venn diagram for the intersection of set A and the complement of set B (A ∩ Bc). Participants confirm that the solution presented is correct, emphasizing that A ∩ Bc can be expressed as A - B. There is clarification that nothing outside of sets A and B should be shaded in the diagram. The conversation highlights the importance of understanding the regions defined by both A and B's complement. Overall, the participants agree on the correct interpretation and representation of the sets involved.
WannaBe
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Draw the venn diagram for A∩Bc

(A Intersection B Completement)

Is my solution correct?

View attachment 1524
 

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  • A-B.png
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Yep, looks good. (Yes)
 
Jameson said:
Yep, looks good. (Yes)
Thank You.

A∩Bc = A-B

So, we don't shade anything in the Universe (rectangle) right? (i.e. outside of A and B)
 
WannaBe said:
Thank You.

A∩Bc = A-B

So, we don't shade anything in the Universe (rectangle) right? (i.e. outside of A and B)

Correct. You're thinking in the right way considering events outside of $A$ and $B$ though. For example, $B^c$ is part of $A$ and everything outside the two circles. However, when we see what is both in $A$ and this region, $B^c$, it is in fact the region you have highlighted in red.
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

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