Driving force from buzzer for jacket of length L

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The discussion centers on understanding the timing of a buzzer's vibrations in relation to its driving force on a jacket of length L. It highlights the concept of resonance, where the buzzer's vibrations can reinforce the motion of the jacket. Due to energy losses in the swinging cloth, there is a phase lag, meaning the cloth's response is slightly delayed compared to the buzzer's vibrations. This phase lag results in a continuous reinforcement of the driving force. The interaction between the buzzer and the jacket exemplifies the principles of resonance in physical systems.
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How do we tell when the buzzer vibrates during the cycle to provide the driving force?

Many thanks!
 
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Callumnc1 said:
How do we tell when the buzzer vibrates during the cycle to provide the driving force?
It's an example of resonance. https://en.wikipedia.org/wiki/Resonance.
Because there are losses in the swinging cloth, it will always be a bit behind the source of vibration (phase lag). As a result, the impetus from the source is reinforcing.
 
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haruspex said:
It's an example of resonance. https://en.wikipedia.org/wiki/Resonance.
Because there are losses in the swinging cloth, it will always be a bit behind the source of vibration (phase lag). As a result, the impetus from the source is reinforcing.
Thank you for your reply @haruspex !
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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