DTFT vs the spectrum of a sampled signal

Click For Summary
SUMMARY

The discussion focuses on the differences between the spectrum of a sampled signal derived from the Dirac delta function and the Discrete-Time Fourier Transform (DTFT). The user expresses confusion over the apparent discrepancies between the two approaches in digital signal processing. It is clarified that while both methods aim to analyze the frequency spectrum of sampled signals, the DTFT is more practical for computational purposes, leading to the Discrete Fourier Transform (DFT). The user concludes that the first equation serves illustrative purposes, while the second is essential for actual calculations.

PREREQUISITES
  • Understanding of the sampling theorem in digital signal processing
  • Familiarity with Dirac delta functions and their properties
  • Knowledge of the Discrete-Time Fourier Transform (DTFT)
  • Basic grasp of complex numbers and Euler's formula
NEXT STEPS
  • Study the relationship between the DTFT and the Discrete Fourier Transform (DFT)
  • Explore the properties of the Dirac delta function in signal processing
  • Learn about the implications of the sampling theorem on signal reconstruction
  • Investigate practical applications of DTFT in digital signal processing
USEFUL FOR

This discussion is beneficial for students and professionals in digital signal processing, particularly those studying the sampling theorem, DTFT, and their applications in real-world signal analysis.

CoolDude420
Messages
199
Reaction score
9

Homework Statement


Hi,

So we started sampling/sampling theorem, dirac delta, DTFT in a digital signal processing module and I'm kinda confused. I understand how to derive the following formulae but these two formulae are so different to each other that I don't understand why?

We are first told that the spectrum of the sampled signal is,
5a20bef40f.png

I completely understand where this comes from (the whole dirac delta part/sifting property and FT property). Okay all makes sense now. Then we are introduced to the DTFT and again I understand the derivation but the result is really different,

ae49470c2c.png


Now, how can these two things be equal to each other? I mean in both cases, we were deriving the frequency spectrum of the sampled signal. Why are the answers so different?

Homework Equations

The Attempt at a Solution

 

Attachments

  • 5a20bef40f.png
    5a20bef40f.png
    18.4 KB · Views: 566
  • a626000d7b.png
    a626000d7b.png
    19.8 KB · Views: 590
  • ae49470c2c.png
    ae49470c2c.png
    15.2 KB · Views: 590
  • Like
Likes   Reactions: berkeman
Physics news on Phys.org
You understand what ## e^{jθ} ## represents? It is ## cosθ + j sinθ ##. The fn coefficients are such that the complex terms cancel out so that you have a real signal.

I don't mean to be rude, I'm just trying to figure what you know.
 
scottdave said:
You understand what ## e^{jθ} ## represents? It is ## cosθ + j sinθ ##. The fn coefficients are such that the complex terms cancel out so that you have a real signal.

I don't mean to be rude, I'm just trying to figure what you know.

So essentially these two are equivalent? Would I be right in saying that the first equation is sort of good for illustration purposes and the second one helps in leading to the DFT for actually calculating?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
5K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
1K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K