Dy/dx = xe^(y-2x), form differntial eqaution

  • #1
dy/dx = xe^(y-2x) , i am asked to form differential equation using this equation . the ans given is (e^-y) = 0.5(e^-2x)(x+0.5) + a , how to get the answer? btw , i have attached my working

BpjWSZj.jpg
 

Answers and Replies

  • #2
BvU
Science Advisor
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Hi John, :welcome:

You really want to
  • post in the homework forum
  • use the template
  • read and follow the guidelines
I hope this reaches you before the mentors lash out: What's the difference between your solution and the given / book solution ?
 
  • #3
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I moved the thread to our homework section.

Check your integration of 2x e2x, for example by calculating the derivative of what you used as integral.
 
  • #4
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dy/dx = xe^(y-2x) , i am asked to form differential equation using this equation .
The equation you wrote already is a differential equation.
john augustine said:
the ans given is (e^-y) = 0.5(e^-2x)(x+0.5) +a
Based on the answer, the problem seems to be asking you to solve the differential equation.
 

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