Dynamics of Rotational Motion and hinge

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The discussion focuses on calculating the angular velocity and angular acceleration of a uniform rod connected to a frictionless hinge at various angles. The rod, with a length of 0.8 m and a mass of 2 kg, is initially held horizontally and then released. The user provided initial calculations, noting that only the results for angular velocity at θ=90° and angular acceleration at θ=0° were correct. Participants emphasized the importance of showing work to identify errors in calculations and suggested using the relationship between torque and angular acceleration for accurate results. The conversation highlights the need for clarity in problem-solving to ensure correct application of physics principles.
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One end of a thin, uniform rod is connected to a frictionless hinge as shown in Figure 1. The rod has a length of 0.8 mand a mass of 2 kg. It is held up in the horizontal position (θ=90∘) and then released.
1)Calculate the angular velocity of the rod at θ=90∘.
2)Calculate the angular acceleration of the rod at θ=90∘.
3)Calculate the angular velocity of the rod at θ=60∘
4)Calculate the angular acceleration of the rod at θ=60∘
5)Calculate the angular velocity of the rod at θ=0∘.
6)Calculate the angular acceleration of the rod at θ=0∘.
1067.PNG

Homework Equations


mgh=1/2 Iw^2
a = ((mgcos)1/2)/I

The Attempt at a Solution


I got these answers and only 1 and 6 were correct
1)0 rad/s
2)74 rad/s^2
3)8.6 rad/s
4)64 rad/s^2
5)12 rad/s
6)0 rad/s^2

Any help is appreciated thank you :)
 
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denny2 said:
Calculate the angular acceleration of the rod at θ=90∘.
3)Calculate the angular velocity of the rod at θ=60∘
4)Calculate the angular acceleration of the rod at θ=60∘
5)Calculate the angular velocity of the rod at θ=0∘.

you are having problem with above - so check expression for angular acceleration.
moment of inertia xangular acceleration = torque on the rod =forcex the the perpendicular distance from the axis of rotation
and for angular velocity one can use the work- energy conversion
work done by a torque is torquex angular displacement= rotational energy
 
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denny2 said:
One end of a thin, uniform rod is connected to a frictionless hinge as shown in Figure 1. The rod has a length of 0.8 mand a mass of 2 kg. It is held up in the horizontal position (θ=90∘) and then released.
1)Calculate the angular velocity of the rod at θ=90∘.
2)Calculate the angular acceleration of the rod at θ=90∘.
3)Calculate the angular velocity of the rod at θ=60∘
4)Calculate the angular acceleration of the rod at θ=60∘
5)Calculate the angular velocity of the rod at θ=0∘.
6)Calculate the angular acceleration of the rod at θ=0∘.
1067.PNG

Homework Equations


mgh=1/2 Iw^2
a = ((mgcos)1/2)/I

The Attempt at a Solution


I got these answers and only 1 and 6 were correct
1)0 rad/s
2)74 rad/s^2
3)8.6 rad/s
4)64 rad/s^2
5)12 rad/s
6)0 rad/s^2

Any help is appreciated thank you :)
We cannot tell where you are going wrong if you do not post your working.
 
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