Dynamics question about boy pulling himself up via pulley

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The discussion revolves around a physics problem involving a 45 kg boy and a 30 kg platform suspended by a pulley. The key calculations include determining the tension in the rope when at rest and when accelerating at 1.5 m/s², as well as the force exerted by the platform on the boy. The correct tension force calculated is 431.25 N, while the force exerted by the platform on the boy is 86.25 N, contrasting with the book's incorrect answer of 131.25 N. The discrepancy arises from whether the weight of the platform should be included in the net force calculations.

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Homework Statement


A 45 kg boy stands on 30 kg platform suspended by a rope passing over a stationary pulley that is free to rotate. The other end of the rope is held by the boy. The masses of the rope and pulley are negligible. Ignore the friction in the pulley.

a) If the rope and the boy are at rest, what is the tension in the rope?

The boy now pulls on the rope so that the acceleration of the boy and the platform is 1.5 m/s^2 upward.

b) What is the tension force in the rope under these new conditions?
c) Under these conditions, what is the force exerted by the platform on the boy?

After a short time, the boy and the platform reach and sustain an upward velocity of 0.3 m/s.

d) Determine the power output of the boy required to sustain this velocity.

Homework Equations



For a-c, we need Newton 2 ƩF = ma.
For d, Power = Fv

The Attempt at a Solution



The problem here is really only part c. The book's answer and my answer agree on the other parts. Unfortunately, the book is wrong often enough that I don't always trust their answer. So, I want confirmation.

Here's what I did. Free Body Diagram on boy yields:
1. Fn upwards (Platform on boy)
2. Ft upwards (boy pulls down on rope, and by Newton 3, his force is Ft upwards). From part b, Ft = 431.25 N
3. mg downwards
ma = 45 * 1.5
In equation form,
Fn + Ft - mg = ma
Fn = ma + mg - Ft = 45*1.5 + 45*10 - 431.25 = 86.25 N
Unfortunately, the book says 131.25 N. I'm guessing that they added the weight of the platform to the ma side of the equation. Who's right? If the book is, why add the weight of the platform to the ma side.
 
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Your solution is correct.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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