Dynamics Question on projectile motion

Click For Summary
To find the horizontal distance traveled by a stone thrown from a cliff, first calculate the time it takes to fall 20 meters using the equation for free fall. The time of fall can be determined from the formula t = √(2h/g), where h is the height of the cliff and g is the acceleration due to gravity. Once the time is known, use the horizontal velocity of 6 m/s to calculate the horizontal distance by multiplying the velocity by the time of fall. The horizontal distance is the product of the constant horizontal speed and the time it takes to reach the ground. This approach neglects air resistance, simplifying the calculations.
leonsilavant
Messages
1
Reaction score
0

Homework Statement



A stone of 0.5kg is thrown horizontally from an edge of a cliff at 6 m/s. If the cliff is 20m, what is the horizontal distance traveled by the stone before landing?

Homework Equations


I am guessing the equations are the standard SUVAT ones and possibly F=ma:

v^2 = u^2+2as
s = (ut) + 1/2(u[t^2])
v = u + at

The Attempt at a Solution



I have no solution so far because i have totally forgotten how to do it. Its for a engineering principles retake exam.

Please help!
 
Physics news on Phys.org
Neglecting air resistance, the horizontal velocity of the rock will remain unchanged while the rock falls to the ground at the bottom of the cliff. What you must do first is calculate how long the rock takes to fall, as if it were dropped directly from the top of the cliff. Once you have the time to fall, you can calculate how far the rock travels horizontally using the velocity and duration of the fall.
 

Similar threads

Replies
19
Views
2K
Replies
4
Views
2K
Replies
19
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
11
Views
1K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K