E on q independent of v - confusing?

  • Context: Undergrad 
  • Thread starter Thread starter jason12345
  • Start date Start date
  • Tags Tags
    Confusing Independent
Click For Summary
SUMMARY

The discussion clarifies that the electric force exerted by a stationary charge on a moving charge is independent of the moving charge's velocity, as established experimentally. The equation F = d/dt (gamma m v) = qE is highlighted to illustrate the relationship between force, charge, and electric field. It is emphasized that in the frame of the moving charge, a magnetic field is present, which is dependent on velocity, complicating the understanding of force in different frames. The lab frame is recommended for simpler calculations.

PREREQUISITES
  • Understanding of basic electromagnetism concepts
  • Familiarity with special relativity principles
  • Knowledge of the Lorentz force equation
  • Experience with frame of reference in physics
NEXT STEPS
  • Study the Lorentz force law in detail
  • Learn about the implications of electric and magnetic fields in different reference frames
  • Explore the concept of gamma factor in special relativity
  • Investigate practical applications of electric fields in moving charges
USEFUL FOR

Physics students, educators, and anyone interested in understanding the nuances of electric forces and their dependence on reference frames in the context of special relativity.

jason12345
Messages
108
Reaction score
0
Many textbooks make the statement that it's found experimentally that the electric force by a stationary charge on on a moving charge is independent of its velocity.

Has this lead to any confusion for people here?

Embarrassingly, I was using this to mean that in the proper frame of the moving charge, it experiences the same force E independent of its velocity. :eek:

Now I realize it simply means that:

F = d/dt (gamma m v) = qE

Of all the concepts in basic relativity I've had problems with, force stands out for me.
 
Physics news on Phys.org
In the frame of the moving charge there will be a magnetic field, and that depends on the velocity. The lab frame makes calculations easier in this case.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 47 ·
2
Replies
47
Views
5K
  • · Replies 38 ·
2
Replies
38
Views
4K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 59 ·
2
Replies
59
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 62 ·
3
Replies
62
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 57 ·
2
Replies
57
Views
8K