I have this really simple differential equation. It needs to be in the form y'+ p(x)y=q(x) to solve it as a linear first order ODE. I am almost embarassed to ask, but I can't seem to get it in exactly this form. Read below. 1. The problem statement, all variables and given/known data y'+3y=2x(e^-3x) Need y'+ p(x)y=q(x) 3. The attempt at a solution Divide both sides by 2x, gives y'/2x + 3y/2x = e^-3x Now here I have y' multiplied by the function 1/2x, but according to the proper linear first order ODE form, Y' needs to be by itself. Can you give me some tips on how to achieve this? I don't know why I can't see it, its probably very simple, but whatever the algebraic manipulation is for this, I seem to have forgotten it. Thank you.