Easy difference quotient question

[Sheneron]

Homework Statement

Using difference quotient I am trying to find f '(0) for 2^x. Basically my question is a questions of algebra but I will show you what I have done thus far.

the limit is as x -> 0

$$\frac{2^x - 2^0}{x - 0}$$

$$\frac{2^x - 1}{x}$$

So my question is what can I do to get x off the bottom.

 

[Dick]

You've probably already proved that the limit x->0 of (e^x-1)/x=1. Try to use that.

 

[Sheneron]

Thanks, that helped.