1. The problem statement, all variables and given/known data The coordinate of an object is given as a function of time by x=4t^2-3t^3, where x is in meters and t is in seconds. Its average acceleration from t=0 to t=2s is: A) -4m/s^2 B) 4m/s^2 C) -10m/s^2 D) 10 m/s^2 E) -13 m/s^2 2. Relevant equations 3. The attempt at a solution I found the second derivative of the position function, which is acceleration, to be a(x)=-18t+8. I plugged 2 and 0 into the equation and subtracted the answer for 0 from the answer for 2. -18t+8 [-18(2)+8]-[-18(0)+8] -28-8 -36 ?