(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The coordinate of an object is given as a function of time by x=4t^2-3t^3, wherexis in meters andtis in seconds. Its average acceleration from t=0 to t=2s is:

A) -4m/s^2

B) 4m/s^2

C) -10m/s^2

D) 10 m/s^2

E) -13 m/s^2

2. Relevant equations

3. The attempt at a solution

I found the second derivative of the position function, which is acceleration, to be a(x)=-18t+8. I plugged 2 and 0 into the equation and subtracted the answer for 0 from the answer for 2.

-18t+8

[-18(2)+8]-[-18(0)+8]

-28-8

-36 ?

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# Homework Help: Easy question, I'm sure its something simple I'm overlooking

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