** sorry. this would be newtons 2nd law of motion. oops. 1. The problem statement, all variables and given/known data Hockey puck with mass 0.160kg at rest at x=0 and t=0 on horizontal frictionless surface. hockey player applies force of 0.250 N until t = 2.00s. ... ... if the same force is applied again at t = 5.00 s what is the position and speed of the puck at t = 7.00s? 2. Relevant equations x(final) = x(initial)+v(initial)t+(1/2)a(t^2) v(final) = v(initial)+at 3. The attempt at a solution at t = 2 seconds, the puck is at x = 3.125m and the velocity is 3.125m/s. the acceleration (from F = ma) is 1.5625 m/s^2. how do I incorportate reapplying the force? i imagine since the surface is frictionless and the acceleration is constant that the puck keeps increasing in velocity right?