Easy Special Relativity Question, Exam two days

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SUMMARY

The discussion focuses on calculating the time it takes for a ball to travel the length of a train from both the ground and train's reference frames using principles of Special Relativity. The participants emphasize the importance of using the Lorentz transformation when velocities approach the speed of light (c) and discuss the relativistic addition of velocities. They conclude that while the time in the train's frame is given by t' = L0/u0, one must consider the relativistic effects when u0 is significant compared to c. The conversation highlights the necessity of analyzing problems from multiple reference frames for a comprehensive understanding.

PREREQUISITES
  • Understanding of Special Relativity concepts, particularly Lorentz transformations.
  • Familiarity with relativistic velocity addition.
  • Knowledge of proper time and time dilation effects.
  • Basic grasp of reference frames in physics.
NEXT STEPS
  • Study the derivation and application of Lorentz transformations in various scenarios.
  • Learn about relativistic velocity addition and its implications in high-speed scenarios.
  • Explore examples of time dilation and proper time calculations in different reference frames.
  • Review the limitations of Newtonian mechanics in the context of Special Relativity.
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Students of physics, educators teaching Special Relativity, and anyone interested in understanding the implications of relativistic effects in high-speed scenarios.

mmmboh
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[PLAIN]http://img811.imageshack.us/img811/3199/trainv.jpg

I have to find how long it takes the ball to travel the distance of the train in the ground frame.

In the train's frame, it is L0/u0.

Is the answer in the ground's frame simply (L0/u0)/(1-v2/c2)^(1/2)?
 
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Use the formula of relativistic addition of velocities to find the speed of the ball relative to the ground.

*** On edit ***
It would help us help you if you posted the sub problems that you have to solve before answering the question.
 
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All we had to do was find the time it would take if spacetime was galilean, and the time it took for the ball to reach the end of the train in the train's frame, both of which are just L0/u0.

The relativistic velocity addition method is messy because the train moves so I can't just divide the length of the in ground frame by that velocity, I'll have to find the total distance it travels, but if your saying my answer is wrong I'll do that...so I can't just take the time an event took in a moving frame and multiply it by gamma?
 
Actually I can just use a simple Lorentz transform on this problem right? I'll take t'=L0/u0, and x'=L0, and for the velocity in gamma I'll use the velocity of the train. That should be right, right?
 
Yes, that'll work.
 
You might consider that the velocity of the ball with respect to the train is also relativistic. Then you would have to find the contracted length of the train in the ball's reference frame and from it the (proper) time it takes the ball to reach the other end. Once you have that, you can use addition of velocities to find the gamma of the ball relative to the ground and then use this gamma to time-dilate the proper time.
 
But that would be a lot more work than just using the lorentz transform equation, wouldn't it..and what do you mean by the velocity of the ball with respect to the train is relativistic? Because the speed of the ball is given with respect to the train, so in that frame we just take it as u0.
 
mmmboh said:
But that would be a lot more work than just using the lorentz transform equation, wouldn't it..
It most certainly would be more work. Are you concerned with quantity or quality of work?
and what do you mean by the velocity of the ball with respect to the train is relativistic? Because the speed of the ball is given with respect to the train, so in that frame we just take it as u0.
I mean what if u0 = 0.9c? You are not given u0 so you may have to assume the more general case. That's why I asked you to post the sub problems mentioned in the statement of the problem.
 
Of course I'm concerned with quality, but I meant if the Lorentz Transform works then why do it the other longer way?...what I mean is...are you saying what I think is wrong, or are you just suggesting another way to do it?
 
  • #10
mmmboh said:
Of course I'm concerned with quality, but I meant if the Lorentz Transform works then why do it the other longer way?...what I mean is...are you saying what I think is wrong, or are you just suggesting another way to do it?
OK. Is Newtonian mechanics as opposed to the Special Theory of Relativity right or is it wrong? The answer is "It depends on the speed of things as compared with the speed of light, c." When you say "I'll take t'=L0/u0, and x'=L0", you are correct if u0 << c, but you are wrong if u0 is comparable to c. So what do you think about how u0 compares with c? It is always safe to use special relativity because Newtonian Mechanics is a limiting case of it. It is not always safe to use Newtonian Mechanics when you don't know whether the speeds are close to the speed of light or not, That's what I'm saying.
 
  • #11
mmmboh said:
Of course I'm concerned with quality, but I meant if the Lorentz Transform works then why do it the other longer way?...what I mean is...are you saying what I think is wrong, or are you just suggesting another way to do it?
If I were you, I'd try calculating the time in all three frames, mostly to satisfy my curiosity to see if it really works out consistently. It also helps to get practice analyzing the same two events in different reference frames, especially a simple problem like this where it doesn't require a lot of effort to do it each way.
 
  • #12
kuruman said:
OK. Is Newtonian mechanics as opposed to the Special Theory of Relativity right or is it wrong? The answer is "It depends on the speed of things as compared with the speed of light, c." When you say "I'll take t'=L0/u0, and x'=L0", you are correct if u0 << c, but you are wrong if u0 is comparable to c.
No, he's correct. In the train's rest frame, the length of the train is L0, and the ball moves with speed u0 and thus reaches the front when t'=L0/u0.
 
  • #13
vela said:
No, he's correct. In the train's rest frame, the length of the train is L0, and the ball moves with speed u0 and thus reaches the front when t'=L0/u0.
Of course. I guess I had a mental lapse.
 

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