Easy Vector Question | Picture Included | Homework Help

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Homework Help Overview

The discussion revolves around a vector problem, with a picture provided by the original poster to illustrate their attempt at a solution. The subject area is likely related to vector analysis and geometry.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationships between unit vectors and the direction of a vector. Questions are raised about finding specific vectors and determining angles between them.

Discussion Status

Some guidance has been offered regarding the relationships between the vectors, and participants are actively engaging with the concepts. There appears to be a progression in understanding, with one participant expressing clarity about the perpendicular nature of certain vectors.

Contextual Notes

The original poster expresses difficulty in understanding the problem despite having made an attempt. There is an implication of reliance on visual aids, as a picture is referenced for context.

Ed Aboud
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Homework Statement



Check the picture.

Homework Equations





The Attempt at a Solution



I'm sure it's very simple but I just can't seem to get it. I've been sitting here staring at the page for a while now with no joy. Check the picture for my attempt.
Thanks very much for any help, greatly appreciated.
 

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Can anyone help with this?
 
well you are correct in saying that [itex]\hat{b}=\frac{\vec{ab}}{|ab|}[/itex] and that [itex]\hat{c}=\frac{\vec{ac}}{|ac|}[/itex].

and if [itex]\vec{ad} = t( \hat{b} - \hat{c})[/itex] what does that tell you about the direction of that vector?

How would you find the vector bc?

then how do you get the angle between two vector lines?
 
Ah I see it now so [itex]\vec{ad} = t ( \hat{cb} )[/itex]
Therefore [itex]\vec{ad}[/itex] is perpendicular to [itex]\hat{cb}[/itex]
Therefore [itex]\vec{ad}[/itex] is the perpendicular bisector of the the line bc.
Thank you very much for your help!
 

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