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EDTA Lab Question/Clarification

  1. Jun 16, 2009 #1
    I weighed out 0.2416 g disodium EDTA and diluted it with about 250 mL of H2O and stuck it in a plastic bottle to use for titration. My question is, to determine the molarity of my stock EDTA standard sol'n, is it just (0.2416g / 292.25 g) / 0.250 L = 0.00331 M? Or do I have to use the VOLUME of EDTA solution used to titrate to the endpoint? (which in my case is 27.54 mL, 27.80 mL, and 27.26 mL respectively). I'm really leaning towards the first equation I wrote, but I'm not 100% sure.

    Also, how would I go about calculating the moles of metal ions that I have in my water sample (50mL). EDTA has a 1:1 stoich ratio with them so would I just (M EDTA x V EDTA) = (M ions x V ions)? So then it would be something like (M EDTA x titration volume) = (M ions x 0.050 L)?

    So, once I figure out the moles of metal ions in solution, to figure out the total hardness of the water sample do I just do (moles of metal ions x MW of CaCO3 mg) / (0.050L) to get it in mg/L (ppm)?

    Thanks in advance for your help.
     
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  3. Jun 16, 2009 #2

    symbolipoint

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    What was the exact volume of EDTA titrant you prepared?

    Moles of metal titrated equals moles of EDTA titrant used, at the titration's endpoint. Did you use a standard Ca+2 solution?
     
  4. Jun 16, 2009 #3
    I prepped it with 250 mL. I put the disodium EDTA in a 250 mL volumetric flask and diluted it to the mark, so I assume it's that. We used water from the faucet in our lab.
     
  5. Jun 16, 2009 #4

    symbolipoint

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    Ponder very carefully the difference between your preparation descriptions which you gave in these two quotes:
    And
    So you seem to have made a standard solution of your EDTA titrant, if what you really did was the second described process. Your two descriptions are not the same. Next, your equation for how the moles are related is correct.
     
    Last edited: Jun 16, 2009
  6. Jun 16, 2009 #5
    Ah sorry, I should've clarified it better. I weighed out the 0.2416 g disodium EDTA and put it in the 250 mL volumetric flask so I could dilute it to the mark. After I did that, I poured the solution into a plastic bottle because its safer that way. (No metal ions in plastic bottle). So in my bottle, there was 250 mL of EDTA solution. Sorry for the mixup.
     
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