Solve Titrimetric Analysis: EDTA & Zinc in Alloy Solution

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SUMMARY

The discussion focuses on calculating the moles of EDTA and zinc in a titration experiment involving a 0.0100 M EDTA solution and a 10.0 mL aliquot of an alloy solution containing zinc. The user successfully calculated the moles of EDTA used, which amounts to 0.000113 moles based on a titration volume of 11.30 mL. The next steps involve determining the moles of zinc in the 10 mL aliquot and extrapolating that to the total volume of 250.0 mL of the alloy solution, utilizing the 1:1 reaction ratio between EDTA and zinc.

PREREQUISITES
  • Understanding of titration principles and stoichiometry
  • Familiarity with molarity calculations
  • Knowledge of EDTA as a chelating agent
  • Basic skills in performing volumetric analysis
NEXT STEPS
  • Calculate the moles of zinc in the 10 mL aliquot using the moles of EDTA
  • Extrapolate the total moles of zinc in the 250.0 mL sample
  • Review titration calculations on resources like titrations.info
  • Explore the use of different indicators in EDTA titrations
USEFUL FOR

Chemistry students, laboratory technicians, and professionals involved in analytical chemistry, particularly those working with titrimetric analysis and metal ion quantification.

ricky912
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Homework Statement


Hello, please help me with this problem.

I've titrated EDTA 0.0100 M into a 10.0 mL aliquot of an alloy solution. My entire alloy same is 250.0 mL.

The EDTA reacted with zinc in a 1:1 ratio, and my best volume is 11.30 mL.

I need to find the moles of EDTA, which I believe I've found.
The moles of zinc in my 10 mL aliquot.
And the total moles of zinc in my 250.0 mL sample.

Homework Equations


The Attempt at a Solution



So far I've found my moles of EDTA in my 11.30 mL.

11.30 ml (1L/1000 mL) = 0.0113 L/EDTA

0.0113 L/EDTA (0.0100 mole/L) = 0.000113 moles of EDTA

After that I'm stuck. Please help me out.

Homework Statement


Homework Equations


The Attempt at a Solution

 
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