[EE - Signals] Question about Discrete-Time Impulse/Discrete-Time Delta

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Discussion Overview

The discussion revolves around the representation of a discrete unit impulse, specifically the function delta[n+1], and its graphical depiction in discrete-time signal processing. Participants explore the implications of shifting the impulse function and the correct way to illustrate it using stem plots.

Discussion Character

  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions the correctness of their representation of delta[n+1] and describes the expected locations of the impulse for various values of n.
  • Another participant confirms that the shift of the impulse function to the left by one unit is correct, drawing a parallel to continuous functions.
  • A later reply reiterates the confirmation and clarifies that at n = -1, the value of the impulse is indeed 1.
  • Further clarification is provided regarding the typical representation of discrete-time signals using stem plots, emphasizing the visual aspects of the plot.

Areas of Agreement / Disagreement

Participants generally agree on the representation of the discrete unit impulse and the implications of shifting it. There is no indication of disagreement in the responses provided.

Contextual Notes

The discussion does not address potential limitations or assumptions regarding the definitions of the discrete unit impulse or the graphical representation methods.

user101
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Quick question about a discrete unit impulse.

If I were to draw delta[n+1], at

... etc
n = -2 ... the point would be at location: 0
n = -1 ... the point would be at location: 1
n = 0 ... the point would be at location: 0
n = 1 ... the point would be at location: 0
n = 2 ... the point would be at location: 0
... etc

What I'm asking is that the line that I have in red... is that correct, with the shift of +1 to the left (an advance signal)?

The reason I'm saying it's -1 is because when n is -1, delta[-1+1] is delta[0] = 1.
 
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Yes that's right... just like ordinary continuous function... f(x+a) is f(x) shifted a units to the left.
 
learningphysics said:
Yes that's right... just like ordinary continuous function... f(x+a) is f(x) shifted a units to the left.

Thanks for the reply. Just to make sure, I would have a "1" dot for y where x = -1 then, correct?
 
user101 said:
Thanks for the reply. Just to make sure, I would have a "1" dot for y where x = -1 then, correct?

Yes, that would be correct but usually discrete time signals are as stem plots... ie a vertical line is drawn from the x-axis up to the dot (nothing is drawn when y=0)... eg:

http://en.wikibooks.org/wiki/Digital_Signal_Processing/Discrete_Data#Stem_Plots

So your plot would have a vertical line segment at n=-1 from the x-axis up to the dot at y=1.
 
Ok, great! Thanks
 

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