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[EE - Signals] Question about Discrete-Time Impulse/Discrete-Time Delta

  1. Aug 30, 2007 #1
    Quick question about a discrete unit impulse.

    If I were to draw delta[n+1], at

    ... etc
    n = -2 ... the point would be at location: 0
    n = -1 ... the point would be at location: 1
    n = 0 ... the point would be at location: 0
    n = 1 ... the point would be at location: 0
    n = 2 ... the point would be at location: 0
    ... etc

    What I'm asking is that the line that I have in red... is that correct, with the shift of +1 to the left (an advance signal)?

    The reason I'm saying it's -1 is because when n is -1, delta[-1+1] is delta[0] = 1.
     
    Last edited: Aug 30, 2007
  2. jcsd
  3. Aug 30, 2007 #2

    learningphysics

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    Yes that's right... just like ordinary continuous function... f(x+a) is f(x) shifted a units to the left.
     
  4. Aug 31, 2007 #3
    Thanks for the reply. Just to make sure, I would have a "1" dot for y where x = -1 then, correct?
     
  5. Aug 31, 2007 #4

    learningphysics

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    Yes, that would be correct but usually discrete time signals are as stem plots... ie a vertical line is drawn from the x-axis up to the dot (nothing is drawn when y=0)... eg:

    http://en.wikibooks.org/wiki/Digital_Signal_Processing/Discrete_Data#Stem_Plots

    So your plot would have a vertical line segment at n=-1 from the x-axis up to the dot at y=1.
     
  6. Sep 1, 2007 #5
    Ok, great! Thanks
     
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