Effect of gravity on the precession rate of a gyroscope

[em2390]

Homework Statement

A certain gyroscope precesses at a rate of 0.60 rad/s when used on earth.
If it were taken to a lunar base, where the acceleration due to gravity is 0.165 g, what would be its precession rate?

Homework Equations

Is the precession rate directly proportional to the gravity exerted on it.

The Attempt at a Solution

Pr=Precession rate we know is Torque/Angular Momentum. The only place i see gravity is in torque (r*ma) so I figured that if the force of gravity is .165 times less, the PR would be .165 times less, or .60 x .165 = 0.099, but that's wrong

 

[chrisk]

For large L the precession is proportional to the acceleration of gravity and independent of the angle of tilt.

$$\omega_p=\frac{mgr}{L}$$

Unless there's more information to the problem, your approach is correct.

 

[em2390]

yea that's what i thought, but for some reason, that's the incorrect answer, and I copied everything from the problem word for word
anyway, thanks for the response