Effective half-life multiple exponential decay

Click For Summary
SUMMARY

The discussion focuses on the calculation of the half-life for a multiple exponential decay represented by the equation A e^{-a x} + B e^{-b x}. The participants explore the analytical challenges in determining the half-life and propose a relationship where if the decay has a half-life t, then a modified decay A e^{-a c x} + B e^{-b c x} has a half-life of t/c. This relationship is supported by empirical observations and a proposed proof using function scaling.

PREREQUISITES
  • Understanding of exponential decay functions
  • Familiarity with half-life concepts in physics and mathematics
  • Basic knowledge of function transformations and scaling
  • Experience with mathematical proofs and analytical reasoning
NEXT STEPS
  • Research the properties of multiple exponential decay functions
  • Study the mathematical derivation of half-life in complex decay scenarios
  • Explore function scaling and its implications in mathematical modeling
  • Investigate numerical methods for approximating half-lives in non-analytical cases
USEFUL FOR

Mathematicians, physicists, and researchers involved in decay processes, as well as students studying advanced calculus and differential equations.

NanakiXIII
Messages
391
Reaction score
0
Say we have a decay of the form

A e^{-a x} + B e^{-b x}.

I haven't had much luck trying to calculate the half-life of such a decay (I'm not sure it's possible, analytically), i.e. solve

A e^{-a x} + B e^{-b x} = \frac{A+B}{2}.

However, if that's not possible, I'm wondering whether there might still be a way to prove that if the above decay has half-life t, then a decay given by

A e^{-a c x} + B e^{-b c x}

has half-life \frac{t}{c}. This seems to be true empirically and would make sense, I think. Does anyone have an idea how one might prove it to be true, though?
 
Physics news on Phys.org
Not really a 'proof', but I think it's rather obvious:

If f(t) is a function, then f(ct) is that function scaled to 1/c of it's size in the t-direction.

So if we plot the graph of these two functions, the point at which f(ct)=f(0)/2 will clearly be at 1/c times the point where f(t) = f(0)/2.



EDIT: I just read the above back to myself and it sounded a bit patronizing to say this was 'obvious' - sorry.

By way of a proof I suppose you could say let

f(x) = A e^{-a x} + B e^{-b x}.

and let

g(x) = A e^{-a c x} + B e^{-b c x}.

then:

g(x) = f(cx)

or equivalently:

g(\frac{y}{c}) = f(y)

So then if 't' is our half life of f, i.e. when:

f(t) = \frac{f(0)}{2}

then:

f(t) = g(\frac{t}{c})
 
Last edited:

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K