- #1
Shinwasha
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Homework Statement
Two parallel-plate capacitors have the same plate area.
Capacitor 1 has a plate separation half that of capacitor 2, and the quantity of charge you place on capacitor 1 is six times the quantity you place on capacitor 2.
How do the two Potentials differences of the capacitors compare V1/V2?
Homework Equations
C=Q/V
The Attempt at a Solution
The one way I was looking at this is that I know that as the as the distance increases the potential difference increases. I was figuring that since no actually numbers were given it would be conceptual passed. I also assumed that C would be the same though I am not sure how distance affects capacitance. V1 = 6q/C and V2= q/C. This is what I'm stuck[/B]