Efficence - Calculate the Force needed to life this load

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Homework Statement


Consider a mechanical car jack. To change a wheel it may need to lift a load of 2000N. Suppose that one rotation of the screw raises the car by 10mm. You apply a force to the end of the lever, 0.5m long, through a full circle. The jack is only 40% efficient. Calculate the force that you have to apply.

(This is a textbook question from OCR, AS Physics.)

Homework Equations



probably to do with moments:
anti-clockwise moments = clockwise moments

work done:
work done = force x perpendicular distance...

GPE:
gravitational pe = mass x g x height

I don't know where to begin, etc..

The Attempt at a Solution



There is answer at the back of the textbook, but I won't show it for now, so that it doesn't affect your way of workings, or anything... I'll show it if needed though.

Thank you for any help!
 
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The work done by the movement of the lever must equal the work done in raising the vehicle. With the jack not being 100% efficient due to friction, you'll have to supply 40% more work to raise it.

So begin thinking about work being done.