Efficiency, power, irradiance and speed problem

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SUMMARY

The discussion focuses on calculating the power output of a solar collector and its relationship to speed in a thermofluid dynamics context. Given a solar irradiance of 1000 W/m² and a collector efficiency of 30%, the solar panel produces 0.3 kW of power. The participant seeks to understand how to relate this power output to speed, specifically when the power available increases from 200,000 W to 200,300 W. The relevant equations include W=Fd and P=F*v, emphasizing that force remains constant while exploring the implications of increased power on speed.

PREREQUISITES
  • Understanding of thermofluid dynamics principles
  • Familiarity with solar energy concepts, specifically solar irradiance
  • Knowledge of basic physics equations related to power, force, and speed
  • Ability to interpret efficiency in energy systems
NEXT STEPS
  • Study the relationship between power output and efficiency in solar collectors
  • Learn about the implications of power changes on vehicle speed using W=Fd and P=F*v
  • Explore the concept of energy conversion efficiency in renewable energy systems
  • Investigate real-world applications of solar power in automotive technology
USEFUL FOR

Students and professionals in thermofluid dynamics, renewable energy engineers, and anyone interested in the practical applications of solar energy in automotive performance.

TyErd
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Homework Statement


I've attached the question


Homework Equations


The problem is I don't know what equation(s) I have to use.


The Attempt at a Solution


This question my part of my thermofluid dynamics course but I cannot find a formula in my textbook that uses an irradiance (1000W/m^2) term.
 

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Think about this problem. You have a 1 m2 solar collector. It is 30% efficient. If 1000 W/m2 is falling on a 1 m2 that is 30% efficient how much power is the solar panel producing(in KW)? Compare with the power of the car.
 
so that means 300W or 0.3kW of power is being produced.
0.3/200=0.0015
how do i relate this to speed
 
If it takes 200,000W to go at speed X how much faster is it likely to go if the power available is increased to 200,300W ? Hint: it's a multiple choice question and its not going to go >50% faster :-).
 
yes its fair enough that it won't go 50% faster or 10% or even 4%, but how would I go about getting an exact answer?
 
How about W=Fd, P = F*v, assume F doesn't change (much)
 
Last edited:

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