Efficient Integral Solver for (z-r*x)/[z^2+r^2-2*z*r*x]^(3/2), x)

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The forum discussion centers on solving the integral ∫(z-r*x)/[z^2+r^2-2*z*r*x]^(3/2) dx. A user attempted various substitutions, including u=z^2+r^2-2*z*r*x, but faced difficulties in simplifying the expression. They also mentioned using tools like Maple and MathWorld's integrator without success. Another participant suggested a substitution that could help replace x and indicated that the integral can be solved without Legendre polynomials.

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int((z-r*x)/[z^2+r^2-2*z*r*x]^(3/2), x)
 
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Is this the integral you want to solve? \int\frac{z-rx}{(z^2+r^2-2zrx)^{3/2}}dx

Could you please show your efforts first, since PF rules state that we must see your work before we can give help you.
 
Last edited:
Would that be:
\int\frac{z-rx}{\sqrt[\frac{3}{2}]{z^{2}+r^{2}-2zrx}}dx
 
sure, i made the substitution u=z^2+r^2-2zrx, but got since du/dx=2zr and i was unable to cancel the x on top. also i let u =(z^2+r^2-2zrx)^3/2, i was unable to solve it. I tried maple, mathworld integrator but was unable to get an answer. I did that so i could at least see what direction to go in. Don't want the solution straight out but help on what direction to go would be great. I know it can be solved using Legendre polynomials but I want to solve it without use of that technique.




cristo said:
Is this the integral you want to solve? \int\frac{z-rx}{(z^2+r^2-2zrx)^{3/2}}dx

Could you please show your efforts first, since PF rules state that we must see your work before we can give help you.
 
ps- how are you posting this mathematical notation? I am young but eager so please be patient with me guys.
 
thebuttonfreak said:
sure, i made the substitution u=z^2+r^2-2zrx, but got since du/dx=2zr and i was unable to cancel the x on top. also i let u =(z^2+r^2-2zrx)^3/2, i was unable to solve it. I tried maple, mathworld integrator but was unable to get an answer. I did that so i could at least see what direction to go in. Don't want the solution straight out but help on what direction to go would be great. I know it can be solved using Legendre polynomials but I want to solve it without use of that technique.

If you use the first substitution then you can replace x by noting that x=(z^2+r^2-u)/2zr. I've not done it, but this may help.

I get an answer when I put it into mathworld's integrator, so you may have typed it in wrong.

To see the mathematical notation, just click on one of the equations to see the code. Then include it in normal text with [ tex ] before and [ /tex ] after the code (without the spaces inside the brackets). See here for the LaTex tutorial.
 
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