thebuttonfreak
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int((z-r*x)/[z^2+r^2-2*z*r*x]^(3/2), x)
The forum discussion centers on solving the integral ∫(z-r*x)/[z^2+r^2-2*z*r*x]^(3/2) dx. A user attempted various substitutions, including u=z^2+r^2-2*z*r*x, but faced difficulties in simplifying the expression. They also mentioned using tools like Maple and MathWorld's integrator without success. Another participant suggested a substitution that could help replace x and indicated that the integral can be solved without Legendre polynomials.
Students and professionals in mathematics, particularly those focused on integral calculus, computational mathematics, and anyone seeking to enhance their problem-solving skills in complex integrals.
cristo said:Is this the integral you want to solve? \int\frac{z-rx}{(z^2+r^2-2zrx)^{3/2}}dx
Could you please show your efforts first, since PF rules state that we must see your work before we can give help you.
thebuttonfreak said:sure, i made the substitution u=z^2+r^2-2zrx, but got since du/dx=2zr and i was unable to cancel the x on top. also i let u =(z^2+r^2-2zrx)^3/2, i was unable to solve it. I tried maple, mathworld integrator but was unable to get an answer. I did that so i could at least see what direction to go in. Don't want the solution straight out but help on what direction to go would be great. I know it can be solved using Legendre polynomials but I want to solve it without use of that technique.