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Homework Statement
int sinh(2x) cosh(2x) dx
u= sinh (2x)
du= 2 cosh (2x)
1/2 int u du
1/2 (u^2)/2
(sinh (2x))^2 / 4
The integral of sinh(2x) cosh(2x) dx can be solved using substitution. By letting u = sinh(2x), the differential du becomes 2 cosh(2x) dx. The integral simplifies to (1/2) ∫ u du, resulting in (sinh(2x))^2 / 4. It is crucial to include the integration constant in the final answer, which was omitted in the discussion. Verifying the solution through differentiation confirms the correctness of the integration process.
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