Efficient Integration: v/(v^2 + 4) Simplified

[Aaron Curran]

I know that if it were 1/(v²+4) then it would be ln(v²+4) but the other v in the numberator is throwing me off, any help would be much appreciated!

 

[Aaron Curran]

Never mind, I figured it out!

 

[SteamKing]

I know that if it were 1/(v²+4) then it would be ln(v²+4)

No, it wouldn't. Can you see why?

but the other v in the numberator is throwing me off, any help would be much appreciated!

There is no such thing as a "numberator". The proper terms for the parts of a fraction are "numerator" and "denominator". You should have learned this long before starting calculus.

 

[Aaron Curran]

No, it wouldn't. Can you see why?
There is no such thing as a "numberator". The proper terms for the parts of a fraction are "numerator" and "denominator". You should have learned this long before starting calculus.

It was a typo haha, I've worked it out now anyway, feel very stupid for making this thread

 

[Mark44]

I know that if it were 1/(v²+4) then it would be ln(v²+4)

No, that is incorrect. You can verify what I said by differentiating ln(v² + 4), which does not result in 1/(v² + 4).

but the other v in the numberator is throwing me off, any help would be much appreciated!

 

[epenguin]

Don't tell us you have got the answer, tell us the answer you have got!