Efficient Method for Finding Constants in Trig Function Power Problem

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SUMMARY

The discussion focuses on finding constants a, b, and c in the equation sin(∅)^5 = asin∅ + bsin3∅ + csin5∅. Participants suggest using the exponential form of sine and the binomial theorem for efficient computation. The binomial theorem simplifies the expansion of (e^{iφ} - e^{-iφ})^5, while an alternative method involves using the identity for sin(A+B) to express sin3φ and sin5φ in terms of sinφ and cosφ. Both methods lead to a polynomial representation in sinφ, streamlining the solution process.

PREREQUISITES
  • Understanding of trigonometric identities, specifically sin(A+B)
  • Familiarity with the binomial theorem
  • Knowledge of complex numbers and their exponential forms
  • Ability to manipulate polynomials in trigonometric functions
NEXT STEPS
  • Study the binomial theorem in depth to understand its applications in trigonometric expansions
  • Explore the exponential form of trigonometric functions for simplification techniques
  • Learn how to derive trigonometric identities from sin(A+B) for various angles
  • Practice polynomial manipulation involving trigonometric functions to enhance problem-solving skills
USEFUL FOR

Students studying trigonometry, mathematicians interested in polynomial expansions, and educators teaching advanced trigonometric identities and their applications.

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Homework Statement


Find constants a, b and c such that
sin(∅)^5=asin∅+bsin3∅+csin5∅



Homework Equations





The Attempt at a Solution


I expressed sin in its complex form (if that's what its called) and put it to the power 5, and then multiplied each bracket out one at a time, and got the correct answers, as checked by wolfram, but I was wondering if there is a quicker way to find the bracket to the power 5 other than just multiplying each bracket out 5 times with its self? This is probably a simple question but I never seem to be able to get the simple stuff. Any help is greatly appreciated. Thanks.

Sorry for the wording; I don't know how to use latex, and it's really ugly just typed out.
 
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Using the exponential form of sin is probably the fastest way to work this out. Expanding [itex](e^{i\phi} - e^{-i\phi})^5[/itex] might be a bit simpler using the binomial theorem: http://en.wikipedia.org/wiki/Binomial_theorem

An alternative to using complex numbers is to use the identity for [itex]\sin(A+B)[/itex] to write [itex]\sin 3\phi[/itex] and [itex]\sin 5\phi[/itex] in terms of [itex]\sin\phi[/itex] and [itex]\cos\phi[/itex]. Then use [itex]\cos^2\phi = 1-\sin^2\phi[/itex] to write the whole thing as a polynomial in [itex]\sin\phi[/itex].
 
Ah, thanks for clearing that up. My tutor used the binomial theorem, but didn't mention it, probably because he's been doing it for so long. Thanks for your help :)
 

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