Efficiently Solve a Tricky Double Integral with These Proven Methods

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SUMMARY

The discussion focuses on evaluating the double integral \int_{0}^{4} \int_{\sqrt{x}}^{2}e^{y^3}dxdy, which presents challenges due to the complexity of the integrand. Participants explored various methods, including changing the order of integration and converting to polar coordinates, but encountered increasingly complicated integrals. Ultimately, a simple substitution for the integral y^2 e^{y^3} was identified as a viable solution approach. The discussion highlights the difficulties associated with Fresnel-type functions and the importance of recognizing simpler substitution methods.

PREREQUISITES
  • Understanding of double integrals and their evaluation techniques
  • Familiarity with Fresnel-type functions and their properties
  • Knowledge of polar coordinates and their application in integration
  • Experience with substitution methods in integral calculus
NEXT STEPS
  • Study the properties of Fresnel-type functions and their integrals
  • Learn advanced techniques for evaluating double integrals
  • Explore substitution methods in greater depth, focusing on exponential functions
  • Practice converting integrals to polar coordinates and solving them
USEFUL FOR

Students and educators in calculus, particularly those dealing with complex integrals, as well as mathematicians seeking efficient methods for evaluating challenging double integrals.

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Homework Statement



Evaluate:

[tex] \int_{0}^{4} \int_{\sqrt{x}}^{2}e^y^3dxdy[/tex]


The Attempt at a Solution



Well that's a Fresnel type function so you can't find an antiderivative for it. I'm pretty sure the point of this assignment isn't Taylor series so I'm quite certain we aren't expected to go down that route.

I tried integrating over x first so my new integral became:

[tex] \int_{0}^{2} \int_{0}^{y^2}e^y^3dydx [/tex]

(did I do this right?)

which after you integrate the inner integral you obtain:

[tex] \int_{0}^{2}y^2e^y^3[/tex]

Which is an even more complicated integral.

I also tried converting to polar coordinates but obtained this even more difficult integral:

[tex] \int_{0}^{2\sqrt{10}} \int_{0}^{\frac{\pi}{2}}e^{{r^3}{cos^3\theta}}d\theta{dr}[/tex]

So any ideas? I tried the two methods we learned in class and the methods which we are supposed to be tested on in this assignment and got nowhere.
 
Physics news on Phys.org
The integral of y^2*e^(y^3) is a simple substitution.
 
Wow, didn't see that, thanks!
 

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