Eigenfunction of \frac{d^2}{dx}-x^2: e^{-0.5x^2} with eigenvalue x^2-1

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SUMMARY

The discussion focuses on verifying whether the function $$e^{-0.5x^2}$$ is an eigenfunction of the operator $$\frac{d^2}{dx^2}-x^2$$. The analysis reveals that applying the operator results in $$e^{-0.5x^2}(x^2-1)-x^2$$, indicating that $$e^{-0.5x^2}$$ does not satisfy the eigenfunction condition. The operator is clearly defined as $$\left(\frac{d^2}{dx^2}-x^2\right)f(x)=\frac{d^2f(x)}{dx^2}-x^2f(x)$$.

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Poirot1
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show that $$e^{-0.5x^2}$$ is an eigenfunction of the operator $$\frac{d^2}{dx}-x^2$$ and finds it's eigenvalue. I get $$e^{-0.5x^2}(x^2-1)-x^2$$ so it doesn't seem like its an eigenfunction.
 
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Re: eigenfunction

The operator is defined as follows.

\[
\left(\frac{d^2}{dx^2}-x^2\right)f(x)=\frac{d^2f(x)}{dx^2}-x^2f(x).
\]
 

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