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Eigenvalues and diagonalizability

  • Thread starter fk378
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This is a concept question..
I'm having trouble understanding why for an n x n matrix A, in order to have eigenvalues, it must have linearly dependent columns (so that a nontrivial solution exists), but for the same A, in order to be diagonalizable, the columns must be linearly INdependent.

The basis for the eigenspace of the former would be the null space, but for the latter, the basis would be the column space since no free variables exist.
 

Answers and Replies

Dick
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It may be difficult to understand because neither of those statements is true. If the columns (or rows) are linearly independent, then it has an INVERSE. A noninvertible matrix can have plenty of eigenvalues. Nor do the columns have to be independent for it to be diagonalizable. The zero matrix is perfectly diagonalizable.
 

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