- #1
Yoonique
- 105
- 0
< Mentor Note -- thread moved to HH from the technical math forums, so no HH Template is shown >
Let A be a square matrix of order n such that A^2 = I
a) Prove that if -1 is the only eigenvalue of A, then A= -I
b) Prove that if 1 is the only eigenvalue of A, then A= I
c) Prove that A is diagonalizable.
For part a and b, I consider A=-I and I then showed that the eigenvalues are -1 and 1 respectively. Is it valid by assuming A=-I and I then proving the eigenvalues are -1 and 1?
If A=-I, Av=λv
-v=λv
therefore, λ=-1.
For part c, I have no clue how to even start. I did some research, and I haven't learn minimal polynomial so I can't use it to prove.
Let A be a square matrix of order n such that A^2 = I
a) Prove that if -1 is the only eigenvalue of A, then A= -I
b) Prove that if 1 is the only eigenvalue of A, then A= I
c) Prove that A is diagonalizable.
For part a and b, I consider A=-I and I then showed that the eigenvalues are -1 and 1 respectively. Is it valid by assuming A=-I and I then proving the eigenvalues are -1 and 1?
If A=-I, Av=λv
-v=λv
therefore, λ=-1.
For part c, I have no clue how to even start. I did some research, and I haven't learn minimal polynomial so I can't use it to prove.
Last edited by a moderator: