Graduate What Does the Book Say About the Eigenvalues of 3x3 Matrices?

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SUMMARY

Every 3x3 quadratic matrix has at least one eigenvalue, as established by the characteristic polynomial which decomposes into linear factors in an algebraically closed field. This means that while a real matrix will always have at least one real eigenvalue, complex matrices can have eigenvalues that are not real. For instance, a diagonal matrix like diag(i, i, i) demonstrates that a complex 3x3 matrix can have a single eigenvalue. The discussion emphasizes the importance of the base field in determining the nature of eigenvalues.

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors
  • Familiarity with characteristic polynomials
  • Knowledge of algebraically closed fields
  • Basic concepts of linear algebra
NEXT STEPS
  • Study the properties of characteristic polynomials in linear algebra
  • Explore the implications of algebraically closed fields on eigenvalues
  • Learn about diagonal matrices and their eigenvalues
  • Investigate the differences between real and complex eigenvalues
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Students and professionals in mathematics, particularly those studying linear algebra, eigenvalue theory, and matrix analysis will benefit from this discussion.

LagrangeEuler
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I found in one book that every quadratic matrix 3x3 has at least one eigenvalue. I do not understand. Shouldn't be stated at least one real eigenvalue? Thanks for the answer.
 
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LagrangeEuler said:
I found in one book that every quadratic matrix 3x3 has at least one eigenvalue. I do not understand. Shouldn't be stated at least one real eigenvalue? Thanks for the answer.
Yes. I assume that the book is primarily assuming real matrices.

We get a characteristic polynomial which decomposes into linear factors in case of an algebraic closed field. So we have ##\chi(t)=-(t-\lambda_1)(t-\lambda_2)(t-\lambda_3)##. But we do not have any knowledge whether the algebraic multiplicities are all one. E.g. ##\lambda_1=\lambda_2=\lambda_3## cannot be ruled out, what commonly is called one eigenvalue, not three.
 
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By definition eigenvalues have to belong to the base field. A qubic polynomial with real quoeficients always has a real root.
 
Yes. But if we have complex 3x3 matrix is it possible to have only one eigenvalue?
 
LagrangeEuler said:
Yes. But if we have complex 3x3 matrix is it possible to have only one eigenvalue?
Like the diagonal matrix ##diag(i, i, i)##?
 
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LagrangeEuler said:
Yes. But if we have complex 3x3 matrix is it possible to have only one eigenvalue?
And what is the book talking about? May be if you revieled the title and the page or quoted the book, we wouldn't have to guess.
 
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