Eigenvalues of coefficient matrix problem

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SUMMARY

The discussion focuses on solving a system of homogeneous differential equations defined by the equations X'_{1}(t) = 141x_{1}(t) - 44x_{2}(t) and X'_{2}(t) = 468x_{1}(t) - 146x_{2}(t). The eigenvalues of the coefficient matrix are derived from the determinant equation det|144-λ -44| = P(λ), leading to the characteristic polynomial λ^{2} + 2λ - 432. The quadratic formula is utilized to find the eigenvalues, which are essential for determining the corresponding eigenvectors and ultimately the general solution for x_{1}(t) and x_{2}(t).

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Homework Statement


Determine the general solution of the system of homogeneous differential equations.
The system of homogeneous differential equations is:
X'_{1}(t) = 141x_{1}(t) - 44x_{2}(t)
X'_{2}(t) = 468x_{1}(t) - 146_{2}(t)

What is Eigenvalues of Coefficient Matrix?
What is corresponding eigenvectors?
What is expression for x_{1}(t)?
What is expression for x_{2}(t)

Homework Equations


The Attempt at a Solution


What is Eigenvalues of Coefficient Matrix?
|144 - 44 | = A
|146 -146|
det|144-λ -44 | = P(λ)
|468 -146-λ|
= (144-λ)(-146-λ) - (-44)(468)
= -21024 -144λ +146λ + λ^{2} + 20592
= λ^{2} +2λ -432
Do I use quadratic equation to find λ?
 
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yes of course, then you find the eigenvectors, then you find your solution to the DE using these eigenvectors
 

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