Eigenvalues of the Frenet formulas and angular velocity

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The discussion centers on the eigenvalues of the curvature matrix K derived from the Frenet-Serret formulas for a circular helix. It is stated that -α² is a nonzero eigenvalue of K², prompting questions about the reasoning behind this assertion without direct computation. Participants highlight that understanding the geometric properties of the helix and the relationship between curvature and torsion can lead to this conclusion. The conversation also touches on the calculation of eigenvalues, with one user providing a formula involving ±α²/(aα² + b²). Ultimately, the discussion seeks clarity on the theoretical basis for identifying -α² as an eigenvalue.
ForMyThunder
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So there's a circular helix parametrized by \vec x(t)=(a\cos(\alpha t), a\sin(\alpha t), bt) and you have the matrix K given in the Frenet-Serret formulas. In the book I'm reading it says that -\alpha^2 is the nonzero eigenvalue of K^2. Can someone explain how they know this is? I understand that you can compute the eigenvalues of the matrix to verify this but how can you say this without computation?
 
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ForMyThunder said:
So there's a circular helix parametrized by \vec x(t)=(a\cos(\alpha t), a\sin(\alpha t), bt) and you have the matrix K given in the Frenet-Serret formulas. In the book I'm reading it says that -\alpha^2 is the nonzero eigenvalue of K^2. Can someone explain how they know this is? I understand that you can compute the eigenvalues of the matrix to verify this but how can you say this without computation?

Can you show me why the eigen value is -alpha^2?

I get +-alpha^2/(a.alpha^2 + b^2)
 

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