JesseM
Science Advisor
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I didn't say that you calculated it using LET, my point was that your calculation must have implicitly snuck in an assumption about the one-way speed of light being c, because LET shows that you can have coordinate systems where the round-trip speed of light is always c but the speed you get for the airplane will be different. However, the speed of that airplane was very small compared to the speed of light so the difference would be small--let me introduce a new numerical example, where I send out a pulse at an approaching spaceship and it bounces back to me after 0.8 seconds, then I send out another pulse 1 second after the first one, and it returns after 0.4 seconds. In this case, if I am in a reference frame constructed in the standard way in relativity, I will conclude that the ship is moving towards me at 0.25c. In my coordinate system, the coordinates of each pulse's emission, reflection and return will be (working in units of light-seconds and seconds, so c=1):Aether said:OK. It may be tomorrow before I am able to put all the steps in here, but the jist is that the round-trip speed of light is isotropic (rotation invariance) in LET as well as SR. So, I ping an airplane twice to measure \Delta x/\Delta t.
I didn't calculate this example using LET; I calculated it to show that I could measure a velocity with one clock.
first pulse emitted: x'=0, t'=0
first pulse hits ship: x'=0.4, t'=0.4
first pulse returns: x'=0, t'=0.8
second pulse emitted: x'=0, t'=1
second pulse hits ship: x'=0.2, t'=1.2
second pulse returns: x'=0, t'=1.4
So you can see that between the first pulse hitting the ship and the second one hitting it, 1.2-0.4=0.8 seconds have passed, and the ship has moved closer to me by 0.4-0.2=0.2 light-seconds, so its speed is (0.2/0.8) c = 0.25c.
Now let's imagine that I am moving at 0.6c in the +x direction in your frame, and we want to know what the coordinates of these events will be in your own rest frame. We can use the Lorentz transform here:
x = 1.25(x' + 0.6t')
t = 1.25(t' + 0.6x'/c^2)
This gives the coordinates:
first pulse emitted: x=0, t=0
first pulse hits ship: x=0.8, t=0.8
first pulse returns: x=0.6, t=1
second pulse emitted: x=0.75, t=1.25
second pulse hits ship: x=1.15, t=1.65
second pulse returns: x=1.05, t=1.75
But now imagine that your frame is actually the rest frame of the ether, and we want to know what the coordinates of these events would be in my rest frame if we used the LET transform instead of the Lorentz transform:
x'=1.25(x - 0.6t)
t'=0.8t
This gives the following coordinates in my LET-transform-rest-frame:
first pulse emitted: x'=0, t'=0
first pulse hits ship: x'=0.4, t'=0.64
first pulse returns: x'=0, t'=0.8
second pulse emitted: x'=0, t'=1
second pulse hits ship: x'=0.2, t'=1.32
second pulse returns: x'=0, t'=1.4
You can see it's still true that the first pulse returned to me 0.8 seconds after it was emitted, that the second pulse was emitted 1 second later, and that the second pulse returned to me after 0.4 seconds. The first pulse had a round-trip distance of 0.8 and a round-trip time of 0.8, while the second had a round-trip distance of 0.4 and a round-trip time of 0.4, so it's true that both pulses have a round-trip speed of c in my coordinate system. But it's no longer true that the ship is traveling at 0.25c towards me; between the time of the first pulse hitting it and the second hitting it, 1.32-0.64=0.68 seconds had passed and the ship had gotten closer by 0.4-0.2=0.2 light-seconds, so its speed is 0.2/0.68 = 0.294c in my coordinate system. So you see, just knowing the timing of the pulses and the round-trip speed of light is not enough to uniquely determine the speed of the ship in any coordinate system; both these things are the same in both my Lorentz-transform-rest-frame and my LET-transform-rest-frame, but the coordinate velocity of the ship is different in these two cases.