Nana Dutchou said:
How does one do to demonstrate that the proper geometry of the rotating disk is not euclidean?
WannabeNewton said:
There is no such thing as "proper" geometry.
DaleSpam said:
What is a "proper geometry"?
DaleSpam said:
I have never heard the term "proper geometry" before. In keeping with the usual meanings of proper time and proper length, I would guess that it is the geometry in the object's rest frame. So I think that may be related to what you are saying A.T.
However, one thing that I see as problematic in your "amount of material" bit is that the amount of material depends on the strain that the structure is under.
DaleSpam said:
Then we are back to post 20 and have just wasted the last 22 posts. I still don't know what "proper geometry" is. As far as I know it is not a standard term in the literature.
Defining a geometry on a three-dimensional physical space consists in attributing an intrinsic measure to each of its segments of parametrized curves and the proper geometry of this physical space is the one which reports the character superposable or not superposable of its segments of parametrized curves (which can be paths of rays of light) by a simple comparaison of their measures.
To define a geometry on a three-dimensional physical space (each point of this space is a world line of an observer) we have to allocate a numerical value (a length) to each of its segments of curves. Mathematically we can define several euclidean geometries on a
unique three-dimensional physical space. We can also define non-euclidean geometries this space! It's easy! But this space has only one proper geometry (knowing that we can change the choice of the standard of lengths).In classical physics each observer possesses a unique three-dimensional physical space on which there is a unique proper geometry and this proper geometry is assumed to be euclidean (this is an intuitive assumption of classical physics).
Are you agreement dear all?In special relativity each inertial coordinate system possesses a unique three-dimensional physical space on which there is a unique proper geometry and this proper geometry is assumed to be euclidean (this is an mathematical assumption of special relativity).
Are you agreement dear all?Mathematically, a segment of parametrized curve (a segment of curve) defined on a three-dimensional physical space is not a segment of world line segment. Each point of this segment of curve is a world line and mathematically, it can be represented by a particular family of world line segments.
Are you agreement dear all?In his text of the post #1, Eintein Albert wants to establish that we can use the theory of special relativity to show that:
(i) We can highlight a non-inertial obserser which possesses a unique three-dimensional physical space.
(ii) The proper geometry of this three-dimensional physical space is not an euclidean geometry.
Are you agreement dear all?
pervect said:
I'm afraid I'm not following a lot of the thread. If the OP can comment whether his idea is a personal theory, or has already been discussed in the literature (for instance one of the papers in Gron) it would be helpful. (Though if it's a personal theory it might not be fit for discussion at PF).
I'm not following AT's ideas on the "proper geometry", like Dale - though the idea sounds interesting.
In his text, Albert Einstein supposes that he is able to specify the equation (in an inertial coordinate system) of each point of
the unique three-dimensional physical space of the rotating observer (the equation of each world line which constitutes this three-dimensional space).
Albert Einstein supposes that it is enough to copy out the equations which are used in classical physics to describe a three-dimensional physical space in rotation with respect to a cartesian and inertial coordinates system.
In the post #1 and #2 at the beginning of this thread I explain that a physicist can argue with that.
Are you agreement dear all?The metric tensor of general relativity is mathematically defined to allocate a numerical value (a length) to each segment of world line which represents a trajectory of matérial body and such a segment is the trajectory of a body in free fall if its measure is optimal.
In his text, Albert Eintein did not define such a metric tensor to show that the three-dimensional physical space of the rotating observer possesses a non-euclidean proper geometry.
Are you agreement dear all?
Nana Dutchou said:
I wrote: why try to verify the accuracy or the inaccuracy of the relation circumference = diameter * pi ?
WannabeNewton said:
It is not inaccurate. The spatial metric geometry of the disk relative to the inertial observers obeys ##C = \pi D## whereas the spatial metric geometry of the disk relative to observers at rest on the disk obeys ##C > \pi D## when the disk is rotating. Neither is any more correct than the other because spatial metric geometry is relative.
Indeed, the proper geometry of a three-dimensional physical space is relative to this three-dimensional physical space ! Mathematically, we cannot compare a segment of parametrized curve defined on a three-dimensional physical space E and a segment of parametrized curve defined on a different three-dimensional physical space E' because mathematically, a point of E is not a point of E' (in other words, because these segments of curves are not represented by the same families of world lines segments).
Each theory in physics can only make assumptions to compare the proper lengths of these segments of curves.
Albert Einstein is working with two separate three-dimensional physical space:
- The first is the family of world lines of observers constanly at rest in an inertial coordinate system.
- The second is the family of world lines of observers constantly at rest on the rotating disc.
Each of these three-dimensional physical space has its own proper geometry (
its own spatial metric geometry you said !). The theory of relativity assumes that the proper geometry of the first is euclidean and Albert Einstein
wants to show that we can infer from the special relativity that the proper geometry of the second is not euclidean.
Mathematically we can define several geometries on a each three-dimensional physical space.
Are you agreement dear all?