1. What current flows through the 11.0 Ω resistor? a) 0.21 A b) 0.27 A c) 0.93 A d) 1.2 A To summarize: V1 = 8.0 V V2 = 5.0 V R1 = 2.0 Ω R2 = 11.0 Ω R2 = 1.0 Ω I know we shouldn't attach pictures, but the diagram does make the question a lot easier to understand. 2. Relevant equations V=IR VT = ε-Ir 3. The attempt at a solution RT = 11.0 + 2.0 + 1.0 = 14.0 Ω VT = 8.0 + 5.0 = 13.0 V IT = V/R = 13.0/14.0 = 0.93 A. And since current should be the same throughout a series circuit, the current through the 11.0 Ω resistor should be 0.93 too. My answer is wrong though. Correct answer: a) 0.21 A, but I don't understand why. Please help me?