Electric Field and charge location

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Homework Help Overview

The discussion revolves around the concept of electric fields and forces related to point charges. The original poster presents a scenario involving a 6.0mC charge experiencing a force in a specified direction, prompting questions about the electric field at that location and the effects of replacing the charge with a different value.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between force and electric field using the equation E=F/Q. There is uncertainty regarding the information needed to solve the problem, particularly about the electric field before the charge was placed. Some participants question how to determine the electric field without additional information.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the relevance of the electric field calculated from the force experienced by the charge. There is an ongoing exploration of the implications of introducing a new charge and how it interacts with the existing electric field.

Contextual Notes

There is a noted lack of information regarding the distance or other charges that may be influencing the electric field, which some participants highlight as a point of confusion. The original poster expresses difficulty in understanding the problem setup and the implications of the charge replacement.

jeremy de leon
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Homework Statement


A 6.0mC charge experiences a force of 2.0x10^-3 N in the +x-direction at a certain point in space.
A. What was the electric field at that location before the charge was placed there
B. What would be the force if the 6mC charge were replaced by a -2.0mC charge?[/B]

Homework Equations


E=F/Q
F=(kQ1Q2)/r^2[/B]

The Attempt at a Solution


I'm actually quite clueless as I think that the given problem lacks information.

I've tried having to use E=F/Q to try and solve for [/B]
 
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jeremy de leon said:
I've tried having to use E=F/Q to try and solve for
... yes, please go on o_O
 
It got cut off, sorry. :)
To solve for the R but it just wouldn't work. So I've got no more ideas for this. I couldn't think of any other solution.
 
jeremy de leon said:
It got cut off, sorry. :)
To solve for the R but it just wouldn't work. So I've got no more ideas for this. I couldn't think of any other solution.
You don't need R to find the field. You were on the right track with E = F/Q.
 
Yeah I got the electric field but how do i get the electric field BEFORE the charge was placed there?

Sorry, this is really confusing me. :/
 
The value that you got will be the field before the new charge is placed. The new charge reacts to the field that is due to other charges, not to its own field. Of course, if another charge were to be brought into the picture, then the new charge would feel the effects of the previous field plus the that of the field due to the original Q, and Q would also feel the new charge.
 

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