Two large, parallel, conducting plates are 7.5 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. An electrostatic force of 1.3 × 10-15 N acts on an electron placed anywhere between the two plates. (Neglect fringing.)
Find the magnitude of the electric field at the position of the electron
The Attempt at a Solution
Hi, my question is: Can I solve the problem by simply considering the plates large and close enough to make the Electric field between them uniform and apply E= F/q to find the electric field? that is:
E= 1.3 x 10-15/1.67 x 10-19 = 7.78 x 103 N/C ?
It feels like i'm ignoring the information of the distance...